CODEWITHSUNDEEP
python
nam
nam

Reputation: 3632

Void print statement in python

I use a internal library that prints a lot (one script could print 40000 lines in total), and I suppose it may have bad impact in performance. This is a library developed by another team in my company and do a lot of calculations, they print to debug errors (and I know this is not a good habit but it's too late because of 100 scripts already on production) and I'm developing a script that uses 100 scripts to produce the result.

How can I decide to turn all this print off ?

I'm not asking how to print these lines to file, but completely omit it

Upvotes: 0

Views: 774

Answers (2)

RichieHindle
RichieHindle

Reputation: 281685

Replace sys.stdout with an object that eats the output:

import sys

class Null:
    def write(self, text):
        pass

    def flush(self):
        pass

print "One"            # This gets output OK
old_stdout = sys.stdout
sys.stdout = Null()
print "Two"            # This disappears
sys.stdout = old_stdout
print "Three"          # Output, back to normal

Upvotes: 7

nemo
nemo

Reputation: 57709

The best way is to simply remove the print statements as there is no overhead whatsoever.

Alternatively, you can redirect the output to /dev/null, which will effectively remove the I/O overhead but will not remove the syscall.

To spare the syscall you can replace sys.stdout with a Writer which does nothing. For example:

class NullWriter():
    def write(self, s): pass

sys.stdout = NullWriter()

Apparently, this has been asked and solved before. Also here.

In case you're using python 3, you can overload the print function as seen in this answer:

def print(*args, **kwargs):
    pass

Upvotes: 2

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