Reputation: 15668
I want to store objects in a map (called result). The objects are created or updated from SQL rows. For each row I read I access the map as follows:
def result = [:]
sql.eachRow('SELECT something') { row->
{
// check if the Entry is already existing
def theEntry = result[row.KEY]
if (theEntry == null) {
// create the entry
theEntry = new Entry(row.VALUE1, row.VALUE2)
// put the entry in the result map
result[row.KEY] = theEntry
}
// use the Entry (create or update the next hierarchie elements)
}
I want to minimize the code for checking and updating the map. How can this be done?
I know the function map.get(key, defaultValue)
, but I will not use it, because it is to expensive to create an instance on each iteration even if I don't need it.
What I would like to have is a get function with a closure for providing the default value. In this case I would have lazy evaluation.
Update
The solution dmahapatro provided is exactly what I want. Following an example of the usage.
// simulate the result from the select
def select = [[a:1, b:2, c:3], [a:1, b:5, c:6], [a:2, b:2, c:4], [a:2, b:3, c:5]]
// a sample class for building an object hierarchie
class Master {
int a
List<Detail> subs = []
String toString() { "Master(a:$a, subs:$subs)" }
}
// a sample class for building an object hierarchie
class Detail {
int b
int c
String toString() { "Detail(b:$b, c:$c)" }
}
// the goal is to build a tree from the SQL result with Master and Detail entries
// and store it in this map
def result = [:]
// iterate over the select, row is visible inside the closure
select.each { row ->
// provide a wrapper with a default value in a closure and get the key
// if it is not available then the closure is executed to create the object
// and put it in the result map -> much compacter than in my question
def theResult = result.withDefault {
new Master(a: row.a)
}.get(row.a)
// process the further columns
theResult.subs.add new Detail(b: row.b, c: row.c )
}
// result should be [
// 1:Master(a:1, subs:[Detail(b:2, c:3), Detail(b:5, c:6)]),
// 2:Master(a:2, subs:[Detail(b:2, c:4), Detail(b:3, c:5)])]
println result
What I learned from this sample:
Upvotes: 3
Views: 2668
Reputation: 50245
You asked for it, Groovy has it for you. :)
def map = [:]
def decoratedMap = map.withDefault{
new Entry()
}
It works the same way you would expect it to work lazily. Have a look at withDefault API for a detailed explanation.
Upvotes: 11