CODEWITHSUNDEEP
linuxbashshell
Saptarshi Chowdhury
Saptarshi Chowdhury

Reputation: 11

How to extract text between a string and a character right before it?

Suppose I have this piece of text:

GINC/weary/crazy/RMSD=2316

I was hoping there was a way to extract what lies between the 2nd forward slash / and /RMSD=2316. In other words, I want to look for the string /RMSD=2316 and extract whatever lies between it and the forward slash that precedes it.

Upvotes: 1

Views: 419

Answers (6)

jaypal singh
jaypal singh

Reputation: 77105

With awk:

awk -F/ '{for(i=1;i<=NF;i++) if($i=="RMSD=2316") print $(i-1)}' t

Upvotes: 2

Ansgar Wiechers
Ansgar Wiechers

Reputation: 200293

Perl solution:

str=GINC/weary/crazy/RMSD=2316
echo "$str" | perl -ne 'print "$1\n" if m|.*?/.*?/(.*)/RMSD=2316|'

Upvotes: 1

gbrener
gbrener

Reputation: 5835

You can use sed:

sed 's/.*\/\([^\/]\+\)\/RMSD=2316/\1/'

This matches all text leading up to a forward-slash, captures all non-forward-slash characters leading up to /RMSD=2316, and replaces the entire match with the captured characters.

Upvotes: 1

iruvar
iruvar

Reputation: 23364

Since you have marked this bash

var='GINC/weary/crazy/RMSD=2316'
var1=${var%/RMSD=2316}
echo $var1
echo ${var1##*/}

Upvotes: 1

perreal
perreal

Reputation: 97948

Using sed, without any positional assumptions:

echo 'GINC/weary/crazy/RMSD=2316' | \
      sed -n 's!.*/\([^/]*\)/RMSD=2316.*!\1!p'

Upvotes: 2

bartimar
bartimar

Reputation: 3534

What about

cut -d/ -f3

-d/ is the slash delimiter

-f3 means third column

Upvotes: 1

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