Reputation: 2539
#include <Python.h>
int isCodeValid() {
char *base = calloc(512, 1);
// free(base);
// base = calloc(512,1);
base = realloc(512, 1);
free(base);
return 1;
}
static PyMethodDef CodecMethods[] = {
{ NULL, NULL, 0, NULL } };
PyMODINIT_FUNC inittest(void) {
//check for the machine code
//Py_FatalError
if (isCodeValid() != 0)
printf("nothing\n");
else {
printf("starting ... \n");
}
(void) Py_InitModule("test", CodecMethods);
}
above is a simple c extension using realloc here is the setup.py
# coding=utf-8
from distutils.core import setup, Extension
import os
cfd = os.path.dirname(os.path.abspath(__file__))
module1 = Extension('test', sources=["test.c"])
setup(name='test', version='0.2', description='codec for test',
ext_modules=[module1],)
import test
after compile with: python2.7 setup.py build_ext --inplace --force
I get the error :
Python(30439) malloc: *** error for object 0x200: pointer being realloc'd was not allocated
*** set a breakpoint in malloc_error_break to debug
but using
free(base);
base = calloc(512,1);
works fine without error
Anything I messed up here?
Upvotes: 0
Views: 183
Reputation: 121971
The first argument to realloc()
must be a pointer, not an int
literal, to a previously allocated memory (or NULL
). The 512
is being cast to a pointer and the complaint is correct that the memory was not previously allocated.
To correct:
/* Don't do this:
base = realloc(base, 512);
because if realloc() fails it returns NULL
and does not free(base), resulting in memory
remaining allocated and the code having no way
to free it: a memory leak.
*/
char* tmp = realloc(base, 512);
if (tmp)
{
base = tmp;
}
Compile with warning level at maximum as the compiler will emit a warning makes pointer from integer or similar. And don't ignore the warnings, preferably treat as errors.
Upvotes: 2