CODEWITHSUNDEEP
linux
jumbopap
jumbopap

Reputation: 4137

getting current directory in linux for argument

I'm learning Linux scripting and trying to set up a function that finds all files in the current directory. I know I could use ls but I'm wondering if there is a way to get the current directory as a command and pass it to an argument. 

#!/bin/bash


check_file() {
for f in $1: 
do
    echo $f
done
}

check_file pwd

This just prints out pwd:, which obviously isn't it.

Upvotes: 7

Views: 12057

Answers (4)

abc
abc

Reputation: 3561

$PDW
the present working directory is stored in the variable named $PWD 

check_file()
 {
  for f in "$(ls $PWD)" 
   do
    echo "$f"
    done
 }
check_file

Display the full working directory name

echo "$PWD"

Display the working directory name

basename "$PWD"

Can also use the symbol *
is a short cut to a list of files in the present working directory . 

echo *

Loop through them :

for item in *
 do
  echo "$item"
 done

Function looping through

check_file()
 {
  for f in * 
   do
    echo "$f"
   done
 }
check_file

Store the present directory name in a variable and use it in a function 

Var=$(basename "$PWD")

func()
{
 echo $1
}
func $Var

Upvotes: 1

Basile Starynkevitch
Basile Starynkevitch

Reputation: 1

A more modern variant is to use the $(...) notation (which can be nested when needed, and is expanded to the output of the command in between $( and matching )) instead of the backquotes, eg

check_file $(pwd)

(but $PWD would work too since shells maintain their PWD variable, see Posix shell).

Read also the advanced bash scripting guide (which can be criticized but is a good start).

Upvotes: 4

nullptr
nullptr

Reputation: 11058

To execute a command and use its output in your script as a parameter, just use back quotes. In your case, it would be:

check_file `pwd`

Upvotes: 6

sasha.sochka
sasha.sochka

Reputation: 14715

PWD variable does exactly what you want. So just replace pwd with $PWD and you are done

Upvotes: 15

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