Reputation: 182
I have a data frame that looks like that:
bin_with_regard_to_strand CLONE3
31 0.14750872
33 0.52735917
28 0.48559060
. .
. .
I want to use this data frame to generate violin plots in such a way that all of the values in CLONE3
corresponding to a given value of bin_with_regard_to_strand
will generate one plot.
Further, I want all of the plots to appear in the same graphic device (I'm using R-studio, and I want all of the plots to appear in one plot window).
Theoretically I could do this with:
vioplot(df$CLONE3[which(df$bin_with_regard_to_strand==1)],
df$CLONE3[which(df$bin_with_regard_to_strand==2)]...)
but since bin_with_regard_to_strand
has 60 different values, this seems a bit ridiculous.
I tried using tapply
:
tapply(df$CLONE3, df$bin_with_regard_to_strand,vioplot)
But that would open 60 different windows (one for each plot).
Or, if I used the add
parameter:
tapply(df$CLONE3, df$bin_with_regard_to_strand,vioplot(add=TRUE))
generated a single plot with the data from all values bin_with_regard_to_strand
(seperated by lines).
Is there a way to do this?
Upvotes: 1
Views: 1104
Reputation: 55
This is an old question, but though I would put out a different solution for getting vioplot to make multiple violin plots on the same graph (i.e. same axes), rather than on different graphics objects like the above answers.
Basically use do.call
to apply vioplot
to a list of data. Ultimately, vioplot is not very well written (can't even set the title, axis names, etc.). I usually prefer base R, but this is a case where ggplot2 options is probably the way to go.
x<-rnorm(1000)
fac<-rep(c(1:10),each=100)
listOfData<-tapply(x,fac,function(x){x},simplify=FALSE)
names(listOfData)[[1]]<-"x" #because vioplot requires a 'x' argument
do.call(vioplot,listOfData)
Upvotes: 0
Reputation: 121568
Another alternative to mfrow
, is to use layout
. It is very handy to organize your plots. You just create a matrix with plots index. Here what you can do. It seems that 60 boxplots is a huge number. Maybe you should organize them in 2 pages.
The code below in function of N (number of plots)
library(vioplot)
N <- 60
par(mar=rep(2,4))
layout(matrix(c(1:N),
nrow=10,byrow=T))
dat <- data.frame(bin_with_regard_to_strand=gl(N,10),CLONE3=rnorm(10*N))
with(dat ,
tapply(CLONE3,bin_with_regard_to_strand ,vioplot))
Upvotes: 0
Reputation: 25736
You could use par(mfrow=c(rows, columns))
(see ?par
for details).
(see also ?layout
for complexer arrangements)
d <- lapply(1:6, function(x)runif(100)) # generate some example data
library("vioplot")
par(mfrow=c(3, 2)) # use a 3x2 (rows x columns) layout
lapply(d, vioplot) # call plot for each list element
par(mfrow=c(1, 1)) # reset layout
Upvotes: 2