CODEWITHSUNDEEP
javascriptformsjsppostonclick
PhantomM
PhantomM

Reputation: 845

form not getting submitted on button click

I am trying the submit the form on button click but want user to confirm whether he is sure or not. I have mutiple submit button on form and I just want pop-up in case of delete. When I make the type of my button submit. My form gets submitted twice If I confirm else It gets submitted once (I don't want it to submitted in that case).

I have multiple form on the page. That's why I am trying to submit the form getting parent Node and not using getElementbyId.

JavaScript function

function deleteEvent(btn){
      var confirmed=confirm('Do you want to delete the event?');
      if(confirmed){
          var f = btn.parentNode;
          f.submit();
          }
      else{
          return false;
          }
    }

HTML Code

<form action="#" method="POST">
<input type="button" name="delete" value="Delete" onClick ="deleteEvent(this)">
</form>

Thanks.

Working Solution:

<input type="submit" name="delete" value="Delete" onClick ="return confirm('Do you want to delete the event?');">

Upvotes: 0

Views: 2147

Answers (1)

sangram parmar
sangram parmar

Reputation: 8726

try this

use onclick="return deleteEvent(this);" if button type is submit

<input type="submit" name="delete" value="Delete" onclick="return deleteEvent(this);">

Upvotes: 2

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