Reputation: 13527
This seems so simple, but I can't seem to figure out how to do it. I have two data sets:
SET1
DATE | TOTAL1 | TOTAL2 | TOTAL3
1 Jun 2013 | 0 | 0 | 5
2 Jun 2013 | 0 | 0 | 12
3 Jun 2013 | 0 | 0 | 34
4 Jun 2013 | 0 | 0 | 50
SET2
DATE | TOTAL1 | TOTAL2 | TOTAL3
1 Jun 2013 | 1 | 2 | 0
2 Jun 2013 | 4 | 12 | 0
3 Jun 2013 | 5 | 12 | 0
4 Jun 2013 | 6 | 10 | 0
I want to create a third dataset the merges these two sets into the following:
SET3
DATE | TOTAL1 | TOTAL2 | TOTAL3
1 Jun 2013 | 1 | 2 | 5
2 Jun 2013 | 4 | 12 | 12
3 Jun 2013 | 5 | 12 | 34
4 Jun 2013 | 6 | 10 | 50
Joining the tables does not work. I need to join them in a way that will add the totals if the dates match up. Any idea how to do this?
Upvotes: 0
Views: 58
Reputation: 21
You can use something similar:
INSERT INTO set3 (date,Total1,Total2,Total3)
SELECT s1.date
,case when s1.date=s2.date then s1.Total1+s2.Total1 end as Total1
,case when s1.date=s2.date then s1.Total2+s2.Total2 end as Total2
,case when s1.date=s2.date then s1.Total3+s2.Total3 end as Total3
FROM set1 s1, set2 s2
WHERE s1.date=s2.date
It works only when you want to add columns with same date. It will not handle rows where the date is different...
Upvotes: 0
Reputation: 496
Use UNION ALL to create 1 table of both sets. Then GROUP BY date and SUM up all totals.
create table set1 (
d date,
total1 number,
total2 number,
total3 number
);
create table set2 (
d date,
total1 number,
total2 number,
total3 number
);
insert into set1 (d, total1, total2, total3) values (to_date('01.06.2013', 'dd.mm.yyyy'), 0,0,5);
insert into set1 (d, total1, total2, total3) values (to_date('02.06.2013', 'dd.mm.yyyy'), 0,0,12);
insert into set1 (d, total1, total2, total3) values (to_date('03.06.2013', 'dd.mm.yyyy'), 0,0,34);
insert into set1 (d, total1, total2, total3) values (to_date('04.06.2013', 'dd.mm.yyyy'), 0,0,50);
insert into set2 (d, total1, total2, total3) values (to_date('01.06.2013', 'dd.mm.yyyy'), 1,2,0);
insert into set2 (d, total1, total2, total3) values (to_date('02.06.2013', 'dd.mm.yyyy'), 4,12,0);
insert into set2 (d, total1, total2, total3) values (to_date('03.06.2013', 'dd.mm.yyyy'), 5,12,0);
insert into set2 (d, total1, total2, total3) values (to_date('04.06.2013', 'dd.mm.yyyy'), 6,10,0);
commit;
select d, sum(total1) as total1, sum(total2) as total2, sum(total3) as total3 from (
select d, total1, total2, total3 from set1
union all
select d, total1, total2, total3 from set2
) group by d
order by d;
Upvotes: 0
Reputation: 1054
SELECT
DATE,
SUM(TOTAL1) AS TOTAL1,
SUM(TOTAL2) AS TOTAL2,
SUM(TOTAL3) AS TOTAL3
FROM
(
SELECT
DATE,
TOTAL1,
TOTAL2,
TOTAL3
FROM
SET1
UNION ALL
SELECT
DATE,
TOTAL1,
TOTAL2,
TOTAL3
FROM
SET2
) SubQueryAlias
GROUP BY
DATE
Upvotes: 5
Reputation: 70638
I'm guessing that you want a FULL JOIN
:
SELECT COALESCE(T1.DATE,T2.DATE) AS DATE,
COALESCE(T1.TOTAL1,0)+COALESCE(T2.TOTAL1,0) AS TOTAL1,
COALESCE(T1.TOTAL2,0)+COALESCE(T2.TOTAL2,0) AS TOTAL2,
COALESCE(T1.TOTAL3,0)+COALESCE(T2.TOTAL3,0) AS TOTAL3
FROM Table1 T1
FULL JOIN Table2 T2
ON T1.DATE = T2.DATE
Upvotes: 2
Reputation: 190944
You still want to do a join but name the columns explicitly, something like this.
SELECT Date, T1.Total1 + T2.Total1 AS TOTAL1, ...
FROM T1 JOIN T2 ON T1.Date = T2.Date
Upvotes: 0