CODEWITHSUNDEEP
phparrays
Source
Source

Reputation: 1011

checking if an array is in an array

I am trying to validate whether or not an array is listed in an array. I am trying to add a product name and url to an session, the session will contain all the products visited by a visitor, but I don't want it to add the same product twice, hence the validation. So if the product is already in the array, I want it to do nothing, but if it doesn't already belong to the array, it needs to be added. This is as far as I got so far. The only issue seems to be the validation.

$viewed_product_url = $viewed_base.$_SERVER['REQUEST_URI'];
if(!isset($_SESSION['products'])) {
$_SESSION['products'] = array('product'=>$products_name,'url'=>$viewed_product_url);
} else {
$found = false;
foreach($_SESSION['products'] as $each_item) {
    while(list($key,$value)=each($each_item)) {
        if($key == 'product' && $value == $products_name) {
            $found = true;
        }
    }
}
if($found==false){
echo 'found';
    $_SESSION['products'][] =    array('product'=>$products_name,'url'=>$viewed_product_url);
}
}

these are the errors I am getting

Warning: Variable passed to each() is not an array or object in C:\xampp\htdocs\customers\msl\product.php on line 10

Warning: Variable passed to each() is not an array or object in C:\xampp\htdocs\customers\msl\product.php on line 10 found

So I just want to know how you can check if an array is already in an multivariate array. Or if there are any other alternatives to achieving what I want here.

Upvotes: 0

Views: 108

Answers (4)

Vishnu Sureshkumar
Vishnu Sureshkumar

Reputation: 2316

$each_item is not an array. That is the reason for the error.

Try this

$viewed_product_url = $viewed_base.$_SERVER['REQUEST_URI'];
if(!isset($_SESSION['products'])) {
$_SESSION['products'] = array('product'=>$products_name,'url'=>$viewed_product_url);
} else {
$found = false;  
if (in_array($viewed_product_url, $_SESSION['products'])) { {
        $found = true;
    }
}
}
if($found==false){
echo 'found';
$_SESSION['products'][] = array('product'=>$products_name,'url'=>$viewed_product_url);

} }

Upvotes: 0

Barmar
Barmar

Reputation: 780655

Change:

$_SESSION['products'] = array('product'=>$products_name,'url'=>$viewed_product_url);

to:

$_SESSION['products'] = array(array('product'=>$products_name,'url'=>$viewed_product_url));

so that you get a 2-dimensional array.

However, I think this is a poor data structure. You should make $_SESSION['products'] an associative array, whose key is the product name. So you add elements to it with:

$_SESSION['products'][$products_name] = $viewed_product_url;

and you find products with:

$found = isset($_SESSION['products'][$products_name]);

Upvotes: 1

martian
martian

Reputation: 20

is_array() function will help you.. http://php.net/manual/en/function.is-array.php

Upvotes: 0

GautamD31
GautamD31

Reputation: 28763

check with is_array like

if(is_array($_SESSION['products']))

and then you can go with foreach

Upvotes: 0

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