Reputation: 13
Sorry about my english I have to get all the records what has the same date at least 2 times , i mean i want to know whos seller make at least 2 sales in the same date.
Table A
id Name Lastname Seller Date Item 23456 Roberto Rodriguez jvazquez 01/01/2013 auto 23423 Roberto Rodriguez jvazquez 01/01/2013 moto 5654 Julián Domínguez rfleita 05/02/2013 lancha 34534653 Romina Santaolaya jvazquez 02/02/2013 moto 346534 Romina Santaolaya rfleita 05/02/2013 auto
Result
23456 Roberto Rodriguez jvazquez 01/01/2013 auto 23423 Roberto Rodriguez jvazquez 01/01/2013 moto 346534 Romina Santaolaya rfleita 05/02/2013 auto 5654 Julián Domínguez rfleita 05/02/2013 lancha
Upvotes: 1
Views: 72
Reputation: 11220
This should give you the result asked for:
SELECT *
FROM TableA
WHERE (Date, Seller) IN (
SELECT Date, Seller
FROM TableA
GROUP BY Date, Seller
HAVING COUNT(*) >= 2
)
Upvotes: 0
Reputation: 416059
SELECT seller, Date, COUNT(*) "Sales"
FROM TableA
GROUP BY Date, seller
HAVING COUNT(*) >= 2
Upvotes: 3
Reputation:
select id,
Name,
Lastname,
Seller,
Date,
Item
from (
select id,
Name,
Lastname,
Seller,
Date,
Item,
count(*) over (partition by date, seller) as cnt
from the_table
) t
where cnt >= 2;
SQLFiddle example: http://www.sqlfiddle.com/#!12/7c0cc/4
If you don't need the additional columns, Joel's answer will be quicker.
Upvotes: 1