Reputation: 5187
I've look at many responses and still cannot figure it out. I know the first line is a little weird, but its because it is inheriting from a super class that sets the headerview to search bar
searchBar = (UISearchBar *)self.tableView.tableHeaderView;
[[searchBar.subviews objectAtIndex:0] removeFromSuperview];
UILabel *label = [[UILabel alloc] initWithFrame:CGRectMake(0, -100, self.view.frame.size.width, 100)];
label.text = @"AAAA";
[searchBar addSubview:label];
UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
[button addTarget:self
action:@selector(aMethod)
forControlEvents:UIControlEventTouchDown];
[button setTitle:@"Show View" forState:UIControlStateNormal];
button.frame = CGRectMake(80.0, -60, 160.0, 40.0);
searchBar.exclusiveTouch = NO;
searchBar.userInteractionEnabled = NO;
label.userInteractionEnabled = NO;
button.userInteractionEnabled = YES;
[searchBar insertSubview:button atIndex:3];
Upvotes: 11
Views: 11578
Reputation: 1827
Here is your answer : searchBar.userInteractionEnabled = NO; If you are going to add a subview to a view that has userInteraction disabled then that subview won't receive touches. I haven't looked very good at your code to see if there are other mistakes.
Look at the frames in the first place :
button.frame = CGRectMake(80.0, -60, 160.0, 40.0);
UILabel *label = [[UILabel alloc] initWithFrame:CGRectMake(0, -100, self.view.frame.size.width, 100);
The button isn't visible at all , and the label the same , the objects are placed outside of bounds and that's why you cannot touch them.
Upvotes: 9
Reputation: 2864
userInteractionEnabled set to NO on a parent view will cascade down to all subviews. Thus, your instance of UIButton will appear unresponsive because the searchBar is disabled.
Upvotes: 10