CODEWITHSUNDEEP
c++arraysint
user77708
user77708

Reputation: 49

C++, Integer and Char array conversion trouble

I have the char array:

char* chararray = new char[33];

and the int:

int exponent = 11111111;

What I want to do, but am confused as to how, is: input the values of exponent into chararray. With the restrictions that exponent has to take up the 2nd to 9th values of chararray. chararray will be all 32 0s,and I want it to become 0xxxxxxxx0000....00, the x's being the 8 digits in exponent.

Furthermore, no build-in conversion functions like atof or atoi. I also want to avoid using Floats or doubles not that you'd really need to.

Note, this is for making IEEE754 32bit values to get some understanding.

Will edit for additional details or clarification if needed.

Upvotes: 1

Views: 659

Answers (1)

raj raj
raj raj

Reputation: 1922

Try this after initializing the array with '0':

for(int i=9; i>=2; i--) {
        chararray[i] = (exponent%10) + '0';
        exponent = exponent/10;
    }
chararray[32] = '\0';

Upvotes: 1

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