CODEWITHSUNDEEP
javaandroidsplitstringtokenizer
Usama Sarwar
Usama Sarwar

Reputation: 9020

Tokenizing or Splitting String

I am having trouble tokenizing or splitting string on the basis of some delimeter. There are two type of Strings that I need to tokenize. Following is the pattern:

   a/b/c/d

and

   a/b//d

I am confused how to get both parsed by one function. As I cannot judge before parsing that which string is about to be parsed. As the data is dynamic. and I get NoSuchElmenet Exception when searching for next token if there is not any. Any help is appreciated.

Upvotes: 0

Views: 143

Answers (2)

smog
smog

Reputation: 11

If you just want to separate the two patterns or determine which one is which, try with the java Pattern class. Below, a quick solution

String testString = "a/b/c//d";
String checkfor = ".*//.*";
boolean matches = Pattern.matches(checkfor, testString);

The Pattern.matches() will search for the occurrence of two "/" followed by each other and return respectively (e.g "//" and not "/... /").

Good luck

Upvotes: 1

luisete89
luisete89

Reputation: 200

I suppose you want to get the tokens {a, b, c, d} or {a, b, d}, so, it's very easy using StringTokenizer class.

Look at this example:

String exampleA = "a/b/c/d";
StringTokenizer tokens=new StringTokenizer(exampleA , "/");
while(tokens.hasMoreTokens()){
    System.out.println(tokens.nextToken());
}

You'll get:

{a, b, c, d}

And, for the second example:

String exampleB = "a/b//d";
StringTokenizer tokens=new StringTokenizer(exampleB, "/");
while(tokens.hasMoreTokens()){
    System.out.println(tokens.nextToken());
}

You'll get:

{a, b, d}

I hope this is useful for you.

Cheers!

Upvotes: 2

Related Questions