CODEWITHSUNDEEP
androidlayout
Zbarcea Christian
Zbarcea Christian

Reputation: 9548

Android add ID to a layout

How do I define an ID to a layout?

I am trying to add an ID to a linearlayout and setting an onclick listener:

XML:

<LinearLayout
   android:id="@+id/?????????"
   android:layout_width="match_parent"
   android:layout_height="match_parent"
   android:orientation="vertical"
   android:onClick="btnHandler" >
</LinearLayout>

Class:

public class MainActivity extends Activity {
    //....

    public void btnHandler(View v){
       switch(v)
       {
          case R.id.????? :
       }
    }
}

Upvotes: 8

Views: 29722

Answers (6)

Juan Carlos Quispe
Juan Carlos Quispe

Reputation: 176

This could work..

XML

<LinearLayout
 android:id="@+id/mylayout"
 android:layout_width="match_parent"
 android:layout_height="match_parent"
 android:orientation="horizontal">
</LinearLayout>

JAVA

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main); 
    LinearLayout myLayout = findViewById(R.id.mylayout);
    myLayout.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Toast.makeText(getApplicationContext(), "Click over Layout", Toast.LENGTH_SHORT).show();
        }
    });

}

Upvotes: 0

nilesh patel
nilesh patel

Reputation: 832

<LinearLayout
   android:id="@+id/lineaLayoutId"
   android:layout_width="match_parent"
   android:layout_height="match_parent"
   android:orientation="vertical"
   android:onClick="btnHandler" >
</LinearLayout>

public class MainActivity extends Activity {
    //....

    public void btnHandler(View v){
       switch(v)
       {
          case R.id.lineaLayoutId :
          break;
       }
    }
}

Upvotes: 1

Raghunandan
Raghunandan

Reputation: 133560

Since you have this

 <LinearLayout
 android:id="@+id/linearlayout"
 android:layout_width="match_parent"
 android:layout_height="match_parent"
 android:orientation="vertical"
 android:onClick="btnHandler" >
</LinearLayout>

You can do as below

  public void btnHandler(View v)
  {
      switch(v.getId()) // use v.getId()
   {
      case R.id.linearlayout :
      break;  // also don't forget the break;
   }

  }

Edit:

If you have button then you can do as below.

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:id="@+id/linearlayout"
    android:onClick="clickEvent"
    android:orientation="vertical" >
<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:id="@+id/bt1"
    android:text="button"   
    android:onClick="clickEvent"
    />

</LinearLayout>

Then in your activity

public void clickEvent(View v)
{
       switch(v.getId())
       {
          case R.id.linearlayout :
              Log.i("......"," linear layout clicked");
          break; 
          case R.id.bt1 :
        Log.i("......"," button clicked");
            break;
       }
}

Upvotes: 8

SceLus
SceLus

Reputation: 1107

Instead of

switch(v)

use

switch(v.getId())

and set your id from the xml

android:id="@+id/idValue"

Upvotes: 5

Flynn81
Flynn81

Reputation: 4168

In onCreate() of your Activity:

findViewById(R.id.?????????).setOnClickListener(this);

And have your Activity implement View.OnClickListener.

@Override
public void onClick(View view) {
    if(view.getId() == R.id.?????????) {
        //your code for on click
    }
}

Upvotes: 0

Ben Weiss
Ben Weiss

Reputation: 17922

The easiest way would be to just add it in your layout xml:

<LinearLayout
   android:id="@+id/myId" <!-- the part where the id is being created -->
   android:layout_width="match_parent"
   android:layout_height="match_parent"
   android:orientation="vertical"
   android:onClick="btnHandler" >
</LinearLayout>

It can then be referenced from your code via your.package.R.id.myId.

Upvotes: 2

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