Reputation: 284
I cannot understand why the second $("tr:even").css("color","yellow");
doesn't work when the first one works correctly.
$(document).ready(function(){
$("#button61").click(function(){
$("tr:even").css("background-color","purple");
$("tr:even").css("color","yellow");
});
});
Upvotes: 0
Views: 75
Reputation: 3
I checked the code, it's alright. Make sure you didn't do any typos. Otherwise explain it clearly if u still have problem. Check console(press F12) for script errors..
Upvotes: 0
Reputation: 123397
you should apply the style to the table cells (since they cover the row) :
$("tr:even td").css({ "background-color": "purple", "color" : "yellow" });
as a sidenote: use css()
method just once with an object as argument, or even better just assign a classname like so
$("tr:even").addClass('highlight');
and define your style in the css
.highlight td {
background-color: purple;
color: yellow;
}
so you can keep off css from javascript, for an improved code mantainance.
Upvotes: 7
Reputation: 16953
It does work - here's a demo of the following JS: http://jsfiddle.net/Grimdotdotdot/UySzs/
$(document).ready(function(){
$("#button61").click(function(){
$("tr:even").css("background-color","purple");
$("tr:even").css("color","yellow");
});
});
But like others have said, just do it all in one line.
Upvotes: 0