Reputation: 29
I am trying to create a function that conjugate a complex number for example A(2, 3) will turn into A(2,-3) by typing ~A i have done a little code below but i guess it's wrong, i hope you can help me slove this. i have quoted the part that i did wrong in the code below.
#include <iostream>
using namespace std;
class Complex
{
private:
double real;
double imaginenary;
public:
Complex();
Complex(double r, double i = 0);
// Declaration
Complex operator~(const Complex & c) const;
Complex operator+(const Complex & c) const;
Complex operator-(const Complex & c) const;
Complex operator*(const Complex & c) const;
Complex operator*(double n) const;
friend Complex operator*(double m, const Complex & c)
{ return c * m; }
friend ostream & operator<<(ostream & os, const Complex & c);
};
Complex::Complex()
{
real = imaginenary = 0;
}
Complex::Complex(double r, double i )
{
real = r;
imaginenary = i;
}
// Definition
Complex Complex::operator~(const Complex & c) const
{
Complex conj;
conj.imaginenary = -1 * imaginenary;
conj.real = real;
}
Complex Complex::operator+(const Complex & c) const
{
Complex sum;
sum.imaginenary = imaginenary + c.imaginenary;
sum.real = real + c.real;
return sum;
}
Complex Complex::operator-(const Complex & c) const
{
Complex diff;
diff.imaginenary = imaginenary - c.imaginenary;
diff.real = real - c.real;
return diff;
}
Complex Complex::operator*(const Complex & c) const
{
Complex mult;
mult.imaginenary = imaginenary * c.imaginenary;
mult.real = real * c.real;
return mult;
}
Complex Complex::operator*(double mult) const
{
Complex result;
result.real = real * mult;
result.imaginenary = imaginenary * mult;
return result;
}
ostream & operator<<(ostream & os, const Complex & c)
{
os << "(" << c.real <<"," << c.imaginenary<<"i)";
return os;
}
int main()
{
Complex A;
Complex B(5, 40);
Complex C(2, 55);
cout << "A, B, and C:\n";
cout << A <<"; " << B << ": " << C << endl;
cout << " complex conjugate is" << ~C << endl;
cout << "B + C: " << B+C << endl;
cout << "B * C: " << B*C << endl;
cout << "10 * B: " << 10*B << endl;
cout << "B - C: " << B - C << endl;
return 0;
}
Upvotes: 3
Views: 8550
Reputation: 29
friend Complex operator*(double m, const Complex & c) { return c * m; }
friend ostream & operator<<(ostream & os, const Complex & c);
Is there anyway to avoid using friend in this problem? because i have read that from the book but not quite understand it.
Upvotes: 0
Reputation: 10808
try
Complex Complex::operator~() const
{
Complex conj;
conj.imaginenary = -1 * imaginenary;
conj.real = real;
return conj;
}
But it might be wiser to remove the operators from the class definition and create (friend) functions instead. It works better with implicit type conversion.
Upvotes: 3
Reputation: 179799
Lots of code, but if you would have compared your operator~
to e.g. operator+
, you would have spotted one detail - there's no return statement.
Upvotes: 3
Reputation: 2417
Complex Complex::operator~(const Complex & c) const
{
Complex conj;
conj.imaginenary = -1 * c.imaginenary;
conj.real = c.real;
return conj;
}
This should do.
Although it's not the best idea to return anything you've allocated inside nonglobal scope, since that region in the memory can be overwritten anytime. And btw it's imaginary, not imaginenary :)
Upvotes: 1
Reputation: 114695
The tilde (~) operator is a unary operator so it shouldn't accept a parameter (it works on *this
). You also forgot to return a value from operator~
.
Complex operator~() const
{
return Complex( real, -1 * imaginenary);
}
See your fixed code here
BTW: It's spelt imaginary.
Upvotes: 9