CODEWITHSUNDEEP
phpajaxfile-upload
Obi-Dan
Obi-Dan

Reputation: 187

PHP - Save image uploaded with AJAX

Given this one a few hours research and thought but I'm not getting anywhere.

I have managed to get an image file to upload through AJAX using a FormData object. When the file reaches the php code I am able to access its info such as 'name' and 'type' by using:

$_FILES['newFile']['name'];
$_FILES['newFile']['type'];

And so on, which means that the file must be uploading as intended, I just can't seem to save it to a file from there.

I have tried:

$file = file_get_contents($_FILES["newFile"]['tmp_name']);
imagejpeg($file, '/img/uploads/' . $_FILES["newFile"]['name']);

But then imagejpeg gives me the error "Expects paramater1 to be resource, string given." So I tried:

$file = imagecreatefromstring(file_get_contents($_FILES["newFile"]['tmp_name']));
imagejpeg($file, '/img/uploads/' . $_FILES["newFile"]['name']);

I now receive the error: /"imagejpeg('/img/uploads/image.jpg'): Failed to open stream. No such file or directory."

Can someone explain how I get the image from the array to a file on disk?

Upvotes: 0

Views: 1286

Answers (3)

Obi-Dan
Obi-Dan

Reputation: 187

Figured it out! Obviously "/img/uploads/" was the issue. PHP doesn't recognize a forward slash as the root directory! My fault! 

move_uploaded_file($_FILES["newFile"]['tmp_name'], $_SERVER['DOCUMENT_ROOT'] . '/img/uploads/' . $_FILES["newFile"]['name']);

Using $_SERVER['DOCUMENT_ROOT'] before the new file path worked perfectly.

Upvotes: 0

bitfiddler
bitfiddler

Reputation: 2115

You have to use the move_uploaded_file function like this:

move_uploaded_file($_FILES["uploaded_file"]["tmp_name"], $pathfilename)

Upvotes: 1

Neel
Neel

Reputation: 19

Use php function move_uploaded_file("$_FILES['newFile']['tmp_name']","Location_where_you_want_to_save");

Upvotes: 0

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