CODEWITHSUNDEEP
javascriptarrays
Marko Vasic
Marko Vasic

Reputation: 690

javascript search in array elements

I have array like this:

var notes = ["user1,date:13/2/2008,note:blablabla", "user1,date:15/2/2008,note:blablabla", "user1,date:17/2/2008,note:blablabla", "user1,date:13/3/2008,note:blablabla"];

And I have 

var search_date="17/2/2008";

I want to find last occurence of note and user for that note. Anyone knows how? Thanks in advance for your reply.

Upvotes: 1

Views: 130

Answers (7)

Misiu
Misiu

Reputation: 4919

var notes = ["user1,date:13/2/2008,note:blablabla", "user1,date:15/2/2008,note:blablabla", "user1,date:17/2/2008,note:blablabla", "user1,date:13/3/2008,note:blablabla"];

var search_date="17/2/2008";
var user, note;

$.each(notes, function(i) {
    var search = new RegExp('\\b' + search_date + '\\b','i');
    // if search term is found
    if (notes[i].match(search)) {
      var arr = notes[i].split(',');
      user = arr[0];
      note = arr[2].substr(5);
    }
}); // end loop

console.log(user);
console.log(note);

example here: http://jsfiddle.net/Misiu/Wn7Rw/

Upvotes: 0

Jon
Jon

Reputation: 1234

For the last occurrence and if performance matters:

var notes = ['user1,date:13/2/2008,note:blablabla', 'user1,date:15/2/2008,note:blablabla', 'user1,date:17/2/2008,note:blablabla', 'user1,date:13/3/2008,note:blablabla'],
    search = '17/2/2008',
    notesLength = notes.length - 1,
    counter,
    highestIndex = null;

for (counter = notesLength; counter >= 0; counter--) {
    if (notes[counter].indexOf(search) !== -1) {
        highestIndex = counter;
        break;
    }
}

// do something with notes[highestIndex]

Upvotes: 0

Willem Mulder
Willem Mulder

Reputation: 14014

var match = JSON.stringify(notes).match("\"([^,]*),date\:"+search_date+",note\:([^,]*)\"");
alert(match[1]);
alert(match[2]);

works ;-)

Upvotes: 1

user405398
user405398

Reputation:

Something like this:

var notes = ["user1,date:13/2/2008,note:blablabla", "user1,date:15/2/2008,note:blablabla", "user1,date:17/2/2008,note:blablabla", "user1,date:13/3/2008,note:blablabla"];
var search_date="17/2/2008";

var res = [];

for(var i = 0; i < notes.length; i++) {
  var note = notes[i];
  if(note.indexOf(search_date) !== -1) {
    res.push(note.substring(note.indexOf('note:') + 1), note.length);
  }
}

var noteYouWanted = res[res.length - 1];

Upvotes: 0

Reason
Reason

Reputation: 1430

for (var i = 0; i < notes; i++) {
    if (notes[i].indexOf(search_date) != -1) {
        // notes [i] contain your date
    }
}

Upvotes: 1

p e p
p e p

Reputation: 6674

Try this: 

var highestIndex = 0;
for (var i = 0; i < notes.length; i++){
    if (notes[i].indexOf(search_date) != -1){
        highestIndex = i;
    }
}
//after for loop, highestIndex contains the last index containing the search date.

Then to get the user, you can parse like this:

var user = notes[highestIndex].substring(0, notes[highestIndex].indexOf(',') - 1);

Upvotes: 1

Balint Bako
Balint Bako

Reputation: 2570

You can iterate the array and check the attribute

or

you can user underscore.js: http://underscorejs.org/#filter

Upvotes: 1

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