Reputation: 4321
My question about XAML:
I want to develop sliding in/out menu in WP8
So, my code is next:
<VisualStateManager.VisualStateGroups>
<VisualStateGroup x:Name="ShowHideMenu">
<VisualStateGroup.Transitions>
<VisualTransition GeneratedDuration="0:0:0.3"/>
</VisualStateGroup.Transitions>
<VisualState x:Name="ShowMenu">
<Storyboard>
<DoubleAnimation Duration="0" To="335" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="stackPanel" d:IsOptimized="True"/>
</Storyboard>
</VisualState>
<VisualState x:Name="HideMenu"/>
</VisualStateGroup>
</VisualStateManager.VisualStateGroups>
And my button code:
<Button Content="Button" Margin="0,0,145,0">
<i:Interaction.Triggers>
<i:EventTrigger EventName="Tap">
<ec:GoToStateAction StateName="ShowMenu"/>
</i:EventTrigger>
</i:Interaction.Triggers>
</Button>
How to make it Show menu if its state is HideMenu and Hide if it is Shown?
Practically it looks like this:
Upvotes: 0
Views: 324
Reputation: 15268
Instead of using a Button
, you could use a ToggleButton
so that you can use the Checked
and Unchecked
events:
<ToggleButton Margin="0,0,145,0">
<ToggleButton.Content>
<TextBlock Text="Button"/>
</ToggleButton.Content>
<i:Interaction.Triggers>
<i:EventTrigger EventName="Checked">
<ec:GoToStateAction StateName="ShowMenu"/>
</i:EventTrigger>
<i:EventTrigger EventName="Unchecked">
<ec:GoToStateAction StateName="HideMenu"/>
</i:EventTrigger>
</i:Interaction.Triggers>
</ToggleButton>
Upvotes: 2