CODEWITHSUNDEEP
css
Nils
Nils

Reputation: 9941

How to position an background-image using an offset but not the linear gradient

I'm trying to style a <select>-Field.
(This is an IE10-only page, so interoperability is only my second concern...)

using:

select
{
  -webkit-appearance: none;
  -moz-appearance: none;
  appearance: none;
  background-image: url(images/select-open.png), linear-gradient(#e3dfdb 50%, #d3cec8);
  background-position: right center;
  background-repeat: no-repeat;
  border: solid 1px #adadad;
  border-radius: 3px;
  cursor: pointer;
  outline: none;
  padding-bottom: 3px;
  padding-left: 3px;
  padding-right: 20px;
  padding-top: 3px;
}

select::-ms-expand
{
  display: none;
}

I get something like: Imeg too far right

Now, if I modify the backgroud position to background-position: right 10px center; then I get something like white padding right.

How can I position the image 10px from the right border while keeping the linear gradient "all the way"? BTW: I feel that adding 10px of transparency to the right side of my image is not an option ;-)

Upvotes: 1

Views: 416

Answers (1)

Mr. Alien
Mr. Alien

Reputation: 157344

What you need to do is separate the position for both the backgrounds using a comma..

background-position: FIRST_IMAGE_POSITION, SECOND_IMAGE_POSITION;

So in your case, image is first and gradient is second so it should be..

select {
  background-position: right center, 0 0; 
  /* Use pixels instead of right and center for better control... 
     where 1st parameter is x and the other parameter is y
   */

  /* Rest stays the same */
}

Upvotes: 6

Related Questions