Reputation: 718
This must be covered somewhere but I'm having difficulty expressing my search criteria, so...
Below are three instance methods declared by the same type.
void Invoke(int timeout);
void Invoke<T>(T data);
T Invoke<T>(int timeout);
I want to invoke the second method, passing an Int32 argument and without using reflection. Options include:
Invoke(1);
Invoke<int>(1);
Invoke((int)1);
Invoke<int>((int)1);
However, none of these calls the desired method. Can I achieve what I want or should I resort to method-renaming?
Note that if the third method did not exist, I could simply do this:
Invoke(1); // Invokes the first method
Invoke<int>(1); // Invokes the second method
Upvotes: 2
Views: 81