CODEWITHSUNDEEP
scala
Yannick Chaze
Yannick Chaze

Reputation: 576

How to parse Int or Double in scala depending on value?

I have a parser class which uses Apache POI to parse Excel files.

When a cell contains 1.0, I would like to convert it to String "1". And when I get 1.1I would like to parse it to "1.1"

How to do that ?

I have try some experiments without success like that:

try
  doubleValue.toInt
catch
{
  case _ => doubleValue.toString
}

Or by using the Integer.parseInt()method.

Upvotes: 0

Views: 179

Answers (1)

pagoda_5b
pagoda_5b

Reputation: 7373

The following code returns an Int if possible, otherwise a Double

if (doubleValue.isValidInt)
  doubleValue.toInt
else
  doubleValue

You must beware that the common type between the two is AnyVal, and sometimes you should declare it explicitly to avoid the compiler to reconvert automatically the Int result to a Double.

P.S. if the outcome must be a String, you can pack the above code in a method and call toString on the result.

Upvotes: 4

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