Reputation: 2619
I'm trying to empty select options when:
id "mClick" is selected, id's "sClick", "cClick" and "srClick" will be emptied.
id "sClick" is selected, id's "cClick" and "srClick" will be emptied.
id "cClick" is selected, id "srClick" will be emptied.
<form action="javascript:void(0);" method="POST" id="lForm">
<table>
<tr>
<td>
<select name="module" id="mClick">
<option value="">Select Mod</option>
<option value="1">Mod 1</option>
<option value="2">Mod 2</option>
<option value="3">Mod 3</option>
</select>
</td>
<td>
<select name="state" id="sClick">
<option value="">Select State</option>
<option value="1">State 1</option>
<option value="2">State 2</option>
</select>
</td>
<td>
<select name="city" id="cClick">
<option value="">Select City</option>
<option value="1">City 1</option>
<option value="2">City 2</option>
</select>
</td>
<td>
<select name="services" id="srClick">
<option value="">Select Services</option>
<option value="1">Services 1</option>
<option value="2">Services 2</option>
</select>
</td>
</tr>
</table>
in scenario 3, i used this function, but it deleted all, except the last select. Any idea's what i'm missing? Thanks
$('#lForm select[id!="mClick"] select[id!="sClick"] select[id!="cClick"] option[value!=""]').remove().end();
Upvotes: 68
Views: 83466
Reputation: 467
I was looking for one line code, what I found after lots of research is the Simplest and Best one line code to remove everything except first.
JQuery,
$('#ddlId option:not(:first)').remove();
Upvotes: 45
Reputation: 688
It's Work
$('#mClick').change(function () {
$('#sClick, #cClick, #srClick').find("option:gt(0)").remove();
});
$('#sClick').change(function () {
$('#cClick, #srClick').find("option:gt(0)").remove();
});
$('#cClick').change(function () {
$('#srClick').find("option:gt(0)").remove();
});
Upvotes: 5
Reputation: 41
asssign general class to your Dropdown then
$('.general option[value!=""]').remove();
this will remove all options except first one whose value is empty Hope this will helps
Upvotes: 2
Reputation: 1891
Try this
yourSelect.find('option').not(':first').remove();
Upvotes: 189
Reputation: 173562
The easiest way to clear the options in the way you're describing is by using options.length = 1
. Also, you can leverage the fact that each drop down clears the ones that logically follow it, so that you only need to declare a single change handler.
$('#lForm select').on('change', function() {
if (this.selectedIndex > 0) {
var $others = $(this).closest('table').find('select'),
current = $others.index(this); // find current
while (++current < $others.length) {
// for each following drop down
$others.get(current).options.length = 1;
}
}
});
I'm not sure how you're going to repopulate the drop downs though :)
Upvotes: 13
Reputation: 993
Try this
$('#lForm select').change(function(){
var $selects = $('#lForm select');
var idx = $selects.index(this);
// Use `val` function to clear the selected values or Use `remove` function to remove the element.
$selects.filter(':gt(' + idx +')').val('');
});
Upvotes: 1
Reputation: 133403
You can use not(:first)
$('#lForm select[id!="makeClick"] select[id!="stateClick"] select[id!="cityClick"] option:not(:first)').remove().end();
Upvotes: 14
Reputation: 7442
you can use the greater than :gt()
selector of jQuery for this
$('#lForm select[id!="makeClick"] select[id!="stateClick"] select[id!="cityClick"] option:gt(0)').remove().end();
This will remove all options that are greater than 0
Upvotes: 19