CODEWITHSUNDEEP
javaregexstring
user1407668
user1407668

Reputation: 617

Regex to validate alpahanumeric or a set of special characters

I have a requirement to ensure that the string has only alphanumeric or a set of characters like + ( ) , ' . - = I tried like

    String regex = "([a-zA-Z0-9]+)|([\\'|\\()|\\+|\\,|\\-|\\.|\\="]+)";
    System.out.println("Regex : " + regex);

    Pattern pattern = Pattern.compile(regex);
    Matcher matcher = pattern.matcher(str);

    if (matcher.matches()) {
        System.out.println("Match");
    } else {
        System.out.println("Not Matching");
    }

Bt it is not working, Can anyone help me please

Thanks in advance

Upvotes: 1

Views: 8749

Answers (3)

Pshemo
Pshemo

Reputation: 124215

It seems that you have compilation problem in 

String regex = "([a-zA-Z0-9]+)|([\\'|\\()|\\+|\\,|\\-|\\.|\\="]+)";

because you have " before ] which ends String. If you want to include " in that set of characters you need to escape it \". If not then just remove it from your regex.

Also | inside [...] will make it normal character, not OR operator so you don't need to use it here. BTW only special character that need escaping in your [...] is -.

Try maybe 

String regex = "([a-zA-Z0-9]+)|(['()+,\\-.=]+)";

or if you want to include " in special characters

String regex = "([a-zA-Z0-9]+)|(['()+,\\-.=\"]+)";

Upvotes: 0

falsetru
falsetru

Reputation: 369044

Use following regular expression:

^[-+=(),'.a-zA-Z0-9]+$

If you want allow zero-length string, replace + with *:

^[-+=(),'.a-zA-Z0-9]*$

Upvotes: 3

Louis Fellows
Louis Fellows

Reputation: 544

It looks like it will not match a whole string containing a mix of alphanumerics and symbols because of the OR in the middle.

e.g. it wont match abcABC()+, but will match abcABC and will match ()+

Try:

([a-zA-Z0-9\\'\\(\\+\\)\\,\\-\\.\\=]+)

Hope this helps!

Upvotes: 4

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