Reputation: 2350
I have a dictionary like:
a = {"staticData":['----','Blue','Green'], "inData":['Indatahere','----','----']}
How can I find that if the dictionary contains "----", in any of the key's values.
Any Javascript function?
EDIT:
What if the case is like this?
a = {"staticData":[], "inData":['Indatahere','----','----']}
It's giving this Error:
TypeError: a[elem].indexOf is not a function
Upvotes: 5
Views: 6807
Reputation: 17288
Use indexOf
to search each array in the a object:
for (elem in a)
{
if (a[elem].indexOf("----") != -1)
alert('---- found at ' + a[elem]);
}
EDIT
For this error: TypeError: a[elem].indexOf is not a function
the browser possibly considers an empty element to be a non-string type; non-string type does not have an indexOf method.
This code checks the length of the array element (if the element is empty before interpreting the indexOf
function.
for (elem in a)
{
if (a[elem].length > 0 && a[elem].indexOf("----") != -1)
alert('---- found at ' + a[elem]);
}
If you wish to support IE < 9, see this post to conditionally add a indexOf definition to the Array object. The post also mentions a Jquery alternative.
The SO post mentioned above lists this Mozilla version of indexOf
function.
if (!Array.prototype.indexOf)
{
Array.prototype.indexOf = function(elt /*, from*/)
{
var len = this.length >>> 0;
var from = Number(arguments[1]) || 0;
from = (from < 0)
? Math.ceil(from)
: Math.floor(from);
if (from < 0)
from += len;
for (; from < len; from++)
{
if (from in this &&
this[from] === elt)
return from;
}
return -1;
};
}
Upvotes: 2
Reputation: 7822
Use Object.getOwnPropertyNames().
You have to write two nested loops. With Object.getOwnPropertyNames you are accessing an array which consists of property names of an object. You will then need to loop over the value of those properties and identify the correct element within this second array.
a = {"staticData":['----','Blue','Green'], "inData":['Indatahere','----','----']}
props = Object.getOwnPropertyNames(a);
for (i=0;i < props.length;i ++) {
for (z = 0; z < a[props[i]].length; z ++) {
//console.log(a[props[i]][z])
if ( (a[props[i]][z]) == '----') {
console.log("I have found an item with ----")
};
}
}
Upvotes: 0
Reputation: 49135
If you know exactly the nesting level of your value, then a quick solution (as suggested in other answers) is possible.
However, if you need a deep traversal search, you're gonna need a recursive version of the solutions, something like:
function FindTraverse(data, match)
{
for (var prop in data)
{
if (!data.hasOwnProperty(prop)) continue;
if (data[prop] == match) return true;
if (typeof data[prop] == 'object' && FindTraverse(data[prop], match)) return true;
}
return false;
}
Examples:
FindTraverse({a:'Foo',b:'Bar'}, 'Bar') // true
FindTraverse(['Foo','Bar'], 'Bar') // true
FindTraverse([{name:'Foo'},{name:'Bar'}], 'Bar') // true
FindTraverse({a:{name:'FooBar'},b:'Bar'}, 'FooBar') // true
However, if you're looking for a more thorough solution, use a framework like jsTraverse
Upvotes: 1
Reputation: 11316
Here is the code:
var a = {"staticData":['----','Blue','Green'], "inData":['Indatahere','----','----']};
for(var key in a){
var value = a[key];
for(var i=0; i<value.length; i++){
if(value[i] == '----') alert("Found '----' in '" + key + "' at index " + i);
};
}
EDIT: Changed iteration over array to normal
way after comment.
Upvotes: 2