CODEWITHSUNDEEP
javascriptregexvalidationpasswordsxregexp
imbecile
imbecile

Reputation: 468

Password Regex with XRegExp

I have a client-side validation regex for a password field which should allow alphabets in all languages supported by Unicode.

This is the existing regex for password:

(?=^.{8,21}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z])

I am using the XRegExp library, and i have tried modifying the regex to include \p{L} but I am unable to get it to pass for passwords like "Ss!11111".

Below is my modified regex:

(?=^.{8,21}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*\\p{L})

I know this question might seem stupid, but i currently have very little time to experiment with this regex. Would be really helpful if someone helped me out and pointed me in the right direction.

Upvotes: 0

Views: 204

Answers (1)

Tim Pietzcker
Tim Pietzcker

Reputation: 336448

You need to double all the backslashes:

(?=^.{8,21}$)((?=.*\\d)|(?=.*\\W))(?![.\\n])(?=.*\\p{L})

Also, I'm not sure of that regex makes much sense. Is this really what you want:

(?=^.{8,21}$)  # Assert length 8-21 characters (why only 21?)
(              # Group 1:
 (?=.*\\d)     # Assert at least one digit in the string
|              # OR
 (?=.*\\W)     # at least one non-alnum character in the string
)              # End of group 1
(?![.\\n])     # Assert that the *first* character isn't a dot or newline (??)
(?=.*\\p{L})   # Assert at least one letter in the string

Upvotes: 1

Related Questions