CODEWITHSUNDEEP
c++3dgridcube
user2572206
user2572206

Reputation: 13

vertex of a 3d cube grid c++

i want to create a 3d cube grid in c++ but i have a problem: once specified the starting point (xs, ys, zs), the ending point (xe,ye,ze) and the number of elements along the three axis..i want to identify the eight corners of each cube.. Setting the origin in (0,0,0) and i,j,k the indexes moving along the three axis i know that:

1° corner is at (i,j,k) 2° corner is at (i+1,j,k) 3° corner is at (i,j+1,k)

and so on..

I don't have an idea on how to take this triples of value and identify one single point inside the three "for loops" on all the elements... Please help me :)

Upvotes: 0

Views: 2780

Answers (1)

Simone Lai
Simone Lai

Reputation: 381

First define a simple struct point3D:

typedef struct {

  float x;
  float y;
  float z;
} point3D;

I wrote this to generate the grid:

//Compute edge sizes 
float x_size = xe - xs;
float y_size = ye - ys;
float z_size = ze - zs;

//Compute steps
float x_step = x_size/n_step;
float y_step = y_size/n_step;
float z_step = z_size/n_step;

//Points per edge (including ending point)
int n = n_step + 1;

//Alloc grid (you can use malloc if you prefer)
point3D grid[n*n*n];

for (int i = 0; i < n; i++) { //move on x axis

  for (int j = 0; j < n; j++) { //move on y axis

    for (int k = 0; k < n; k++) { //move on z axis

      point3D p;
      p.x = xs + x_step * i;
      p.y = ys + y_step * j;
      p.z = zs + z_step * k;
      grid[i+n*j+n*n*k] = point3D;
    } 
  }
}

To take the 8 corner points use:

point3D corner = grid[n_step*x + n*n_step*y + n*n*n_step*z];

with:

   (x, y, z)
1: (0, 0, 0)
2: (0, 0, 1)
3: (0, 1, 0)
4: (0, 1, 1)
5: (1, 0, 0)
6: (1, 0, 1)
7: (1, 1, 0)
8: (1, 1, 1)

Upvotes: 2

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