Reputation: 71939
I know storing lists as strings is not wise, but I have to deal with that to export some data stored that way. I also know the FIND_IN_SET
function, which returns the index of a certain string in a list:
SELECT FIND_IN_SET('bar', 'foo,bar,baz');
-- selects 2
Is there any built-in function (or combination of functions) to get the string in a particular index of the list? I'm looking for something like this:
SELECT IN_SET_AT_INDEX(2, 'foo,bar,baz');
-- selects 'bar'
I'd like to avoid a split-like function that makes the list a separate table, if possible.
Upvotes: 3
Views: 3267
Reputation: 562731
SUBSTRING_INDEX()
can do this, sort of:
mysql> SELECT SUBSTRING_INDEX(SUBSTRING_INDEX('foo,bar,baz', ',', 2), ',', -1) AS middle_one;
+------------+
| middle_one |
+------------+
| bar |
+------------+
Upvotes: 9
Reputation: 1270633
Yes, but it requires just a little trickery. The basis is substring_index()
, but that gets everything up to the nth entry. Then I use reverse()
twice and another substring_index()
:
select reverse(substring_index(reverse(substring_index('foo,bar,baz', ',', 2)), ',', 1))
In your case, the transformations are:
original string: 'foo,bar,baz'
after substring_index(..., 2) 'foo,bar'
after inner reverse 'rab,oof'
after substring_index(..., 1) 'rab'
after outer reverse 'bar'
Upvotes: 1