Reputation: 3803
There are 3 (which I know) ways to suppress the "unused variable" warning. Any particular way is better than other ?
First
- (void)testString:(NSString *)testString
{
(void)testString;
}
Second
- (void)testString:(NSString *)__unused testString
{
}
Third
- (void)testString:(NSString *)testString
{
#pragma unused(testString)
}
Upvotes: 17
Views: 27684
Reputation: 7360
If you are compiling with GCC, you can take advantage of attribute extensions to set the 'unused' attribute. Like this:
int somevar __attribute__((unused));
It also works for unused parameter warnings (-Wunused-parameter)
To make it shorter to write I am using this macro:
#define _U_ __attribute__((unused))
And declare like this:
int somevar _U_ ;
Upvotes: 7
Reputation: 104698
This is the approach I use: cross platform macro for silencing unused variables warning
It allows you to use one macro for any platform (although the definitions may differ, depending on the compiler), so it's a very portable approach to express your intention to popular compilers for C based languages. On GCC and Clang, it is equivalent of wrapping your third example (#pragma unused(testString)
) into a macro.
Using the example from the linked answer:
- (void)testString:(NSString *)testString
{
MONUnusedParameter(testString);
}
I've found this approach best for portability and clarity, in use with some pretty large C, C++, ObjC, and ObjC++ codebases.
Upvotes: 8
Reputation: 378
One way to do it is just to assign a variable pointlessly after it is declared For example:
int foo;
foo = 0;
This should suppress the unused variable warning. It is just a pointless assignment.
But otherwise I would agree with ouah, the first method is the most reliable, if you must choose from those three.
Upvotes: -11