CODEWITHSUNDEEP
javaregex
Sara
Sara

Reputation: 2436

finding number between 2 parenthesis using regular expression

In a line I may have (123,456) I want to find it using pattern in java. What I did is:

Pattern pattern = Pattern.compile("\\W");
Matcher matcher = pattern.matcher("(");
while (matcher.find()) {
      System.out.print("Start index: " + matcher.start());
      System.out.print(" End index: " + matcher.end() + " ");
}

Input: This is test (123,456) Output:Start index: 0 End index: 1 ( Why??

Upvotes: 0

Views: 909

Answers (2)

bsd
bsd

Reputation: 2717

I am not sure how \W is going to match it. \W matches a non word character.

You will also have to escape those backslashes.

Round brackets need to be escaped , as by default they are used for grouping.

Maybe the regex you meant was

Pattern pattern = Pattern.compile("\\([,\\d]+\\)");
Matcher matcher = pattern.matcher(inputString);

while (matcher.find()) {
    String matched = matcher.group();
    //Do something with it  
}

Explanation:

\\(     # Match (
[,\\d]+ # Match 1+ digits/commas. Don't be surprised if it matches (,,,,,,)
\\)     # Match )

Upvotes: 4

Bohemian
Bohemian

Reputation: 425043

To do it in one line:

String num = str.replaceAll(".*\\(([\\d,]+)\\).*", "$1");

Upvotes: 1

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