CODEWITHSUNDEEP
linuxsh
user2294256
user2294256

Reputation: 1049

How to get my expected search result using grep on Linux

I am trying to find out which files contains this text 'roads' on the server, so I use this command: grep -rl 'roads'. But it shows lots of such files:

./res/js/.svn/entries
./res/js/.svn/all-wcprops
./res/styles/.svn/entries
./res/styles/.svn/all-wcprops
./res/images/.svn/entries

I do not want this folder .svn show in the search result because this is just for version control, it means nothing for me, so is there a way that I can do this: if the result contains .svn, then it does not show up in the final result. e.g. below three files contain the text 'roads':

 check.php 
./res/js/.svn/entries
./res/js/.svn/all-wcprops

Then the result only shows:

check.php

Upvotes: 0

Views: 103

Answers (2)

rakib_
rakib_

Reputation: 142615

grep has a feature to exclude a particular directory, called "--exclude-dir", so simply you can pass .svn as "--exclude-dir" param, like below:

        "grep -rl --exclude-dir=.svn ./ -e roads"

Upvotes: 1

Dolda2000
Dolda2000

Reputation: 25855

One simple way is to simply grep away your false positives:

grep -rl roads . | grep -v '/\.svn/'

If you want to be more efficient and not spend time searching through the SVN files, you can filter them away before grepping through them:

find -type f | grep -v '/\.svn/' | xargs grep -l roads

Upvotes: 1

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