CODEWITHSUNDEEP
sqlsql-server
InTheWorldOfCodingApplications
InTheWorldOfCodingApplications

Reputation: 2616

Finding a Top Level Parent in SQL

I have got two tables as following

Table Person

  Id   Name
   1    A
   2    B
   3    C
   4    D
   5    E

Table RelationHierarchy

ParentId   ChildId
   2         1
   3         2
   4         3

This will form a tree like structure

          D
          |
          C
          |
          B
          |
          A

ParentId and ChildId are foreign keys of Id column of Person Table

I need to write SQL that Can fetch me Top Level Parent i-e Root. Can anyone suggest any SQL that can help me accomplish this

Upvotes: 24

Views: 69303

Answers (9)

Tinman
Tinman

Reputation: 111

I've used this pattern to associate items in a hierarchy with the item's root node.

Essentially recursing the hierarchies maintaining the values of the root node as additional columns appended to each row. Hope this helps.

with allRows as (
    select ItemId, ItemName, ItemId [RootId],ItemName [RootName] 
    from parentChildTable
    where ParentItemId is null
    union all
    select a1.ItemId,a1.ItemName,a2.[RootId],a2.[RootName]
    from parentChildTable a1
    join allRows a2 on a2.ItemId = a1.ParentItemId
)   

select * from allRows

Upvotes: 10

Zanyar Jalal
Zanyar Jalal

Reputation: 1894

WITH CTE_MyTable AS (
    SELECT        Id, ParentId, NULL As RootParent, 1 As Lvl
    FROM            dbo.Ministry
    UNION ALL
    SELECT        a.id, b.ParentId, a.ParentId As RootParent, Lvl + 1
    FROM            CTE_MyTableAS a INNER JOIN
                                               dbo.MyTableAS b ON a.ParentId = b.Id
)
, CTE_Ministry_RN AS  (
    SELECT Id, RootParent, ROW_NUMBER() OVER (PARTITION BY Id ORDER BY Lvl DESC) RN
    FROM CTE_Ministry
)

SELECT Id, ISNULL(RootParent, Id) As RootParent
FROM CTE_Ministry_RN
WHERE RN = 1

Upvotes: 0

Eqbal Sajadi
Eqbal Sajadi

Reputation: 97

Get all top parents using path

path format: rootId/.../parentId/nodeId/

select t1.path from nodes t1 inner join nodes t2
on t1.path like t2.path+'%' 
group by t1.path 
having len(t1.path)-len(replace(t1.path, '/', ''))
=min(len(t2.path)-len(replace(t2.path, '/', '')))

Upvotes: 1

Gordon Linoff
Gordon Linoff

Reputation: 1271003

The only way you can do this in "standard" SQL is to assume a maximum depth for the tree, and then do joins for each level. The following gets the top level id:

select rh1.ChildId,
       coalesce(rh4.parentid, rh3.parentid, rh2.parentid, rh1.parentid) as topLevel
from RelationshipHierarchy rh1 left outer join
     RelationshipHierarchy rh2
     on rh1.parentId = rh2.childId left outer join
     RelationshipHierarchy rh3
     on rh2.parentId = rh3.childId left outer join
     RelationshipHierarchy rh4
     on rh3.parentId = rh4.childId;

If you want the name, you can just join it in:

select rh1.ChildId,
       coalesce(rh4.parentid, rh3.parentid, rh2.parentid, rh1.parentid) as topLevel,
       p.name
from RelationshipHierarchy rh1 left outer join
     RelationshipHierarchy rh2
     on rh1.parentId = rh2.childId left outer join
     RelationshipHierarchy rh3
     on rh2.parentId = rh3.childId left outer join
     RelationshipHierarchy rh4
     on rh3.parentId = rh4.childId left outer join
     Person p
     on p.id = coalesce(rh4.parentid, rh3.parentid, rh2.parentid, rh1.parentid);

Upvotes: 1

Nenad Zivkovic
Nenad Zivkovic

Reputation: 18559

You can use recursive CTE to achieve that:

DECLARE @childID INT 
SET @childID  = 1 --chield to search

;WITH RCTE AS
(
    SELECT *, 1 AS Lvl FROM RelationHierarchy 
    WHERE ChildID = @childID

    UNION ALL

    SELECT rh.*, Lvl+1 AS Lvl FROM dbo.RelationHierarchy rh
    INNER JOIN RCTE rc ON rh.CHildId = rc.ParentId
)
SELECT TOP 1 id, Name
FROM RCTE r
inner JOIN dbo.Person p ON p.id = r.ParentId
ORDER BY lvl DESC

SQLFiddle DEMO

EDIT - for updated request for top level parents for all children:

;WITH RCTE AS
(
    SELECT  ParentId, ChildId, 1 AS Lvl FROM RelationHierarchy 

    UNION ALL

    SELECT rh.ParentId, rc.ChildId, Lvl+1 AS Lvl 
    FROM dbo.RelationHierarchy rh
    INNER JOIN RCTE rc ON rh.ChildId = rc.ParentId
)
,CTE_RN AS 
(
    SELECT *, ROW_NUMBER() OVER (PARTITION BY r.ChildID ORDER BY r.Lvl DESC) RN
    FROM RCTE r

)
SELECT r.ChildId, pc.Name AS ChildName, r.ParentId, pp.Name AS ParentName
FROM CTE_RN r
INNER JOIN dbo.Person pp ON pp.id = r.ParentId
INNER JOIN dbo.Person pc ON pc.id = r.ChildId
WHERE RN =1

SQLFiddle DEMO

EDIT2 - to get all persons change JOINS a bit at the end:

SELECT pc.Id AS ChildID, pc.Name AS ChildName, r.ParentId, pp.Name AS ParentName
FROM dbo.Person pc 
LEFT JOIN CTE_RN r ON pc.id = r.CHildId AND  RN =1
LEFT JOIN dbo.Person pp ON pp.id = r.ParentId

SQLFiddle DEMo

Upvotes: 36

Brandon
Brandon

Reputation: 10058

Try this.

The recursive CTE will find the person and walk up the hierarchy until it finds no parent.

-- This CTE will find the ancestors along with a measure of how far up
-- the hierarchy each ancestor is from the selected person.
with ancestor as (
  select ParentId as AncestorId, 0 as distance
  from RelationHierarchy
  where CHildId = ?

  union all

  select h.ParentId, a.distance + 1
  from ancestor a inner join RelationHierarchy rh on a.AncestorId = rh.ChildId
)
select AncestorId
from ancestor
where distance = (select max(distance) from ancestor)

Upvotes: 3

user359040
user359040

Reputation:

To find all top-level parents, use a query like:

select p.Name
from Person p
where not exists
(select null
 from RelationHierarchy r
 where r.ChildId = p.Id)

SQLFiddle here.

To find the top-level parent of a specific child, use:

with cte as
(select t.ParentId TopParent, t.ChildId 
 from RelationHierarchy t
 left join RelationHierarchy p on p.ChildId = t.ParentId
 where p.ChildId is null
 union all
 select t.TopParent TopParent, c.ChildId 
 from cte t
 join RelationHierarchy c on t.ChildId = c.ParentId)
select p.name
from cte h
join Person p on h.TopParent = p.Id
where h.ChildId=3 /*or whichever child is required*/

SQLFiddle here.

Upvotes: 6

user1957877
user1957877

Reputation:

Give this a go:

    select id,name
    from person p
    where not exists
    (
    select 1 
    from relationhierarchy r
    where r.childid= p.id
    )
    and exists
    (
    select 1 
    from relationhierarchy r
    where r.parentid= p.id
    )

It is not enough to just see if a child id exists as in your example E is present in the person table but not in the relationshiphierarchy table.

Upvotes: 0

jmarceli
jmarceli

Reputation: 20182

Something like this will work for above example:

SELECT ParentId FROM RelationHierarchy 
WHERE ParentId NOT IN (SELECT CHildId FROM RelationHierarchy)

Upvotes: 2

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