CODEWITHSUNDEEP
eclipserestservletsjersey
Jason Allen
Jason Allen

Reputation: 370

Jersey REST Web Service, Tomcat, Eclipse and 404's

I've read through a number of posts, but just can't seem to solve my problem. You'll also see tons of posts very similar to this one, even the same tutorial. Even following them, I can't seem to get to the answer.

Essentially, I'm trying to follow the simple tutorial at: http://www.vogella.com/articles/REST/

I've made a few changes to make it compatible with Jersey 2.x

I'm using: Eclipse Tomcat 6 (Deployed/Run as within Eclipse) jaxrs-ri-2.0 I've enabled the JAX-RS Facet in Eclipse

Everything builds fine Tomcat starts fine within Eclipse I can get to a static page content via:

http://localhost:8080/RestTEST2/index.html

However, when I try to access my service via:

http://localhost:8080/RestTEST2/jaxrs/hello

I receive a 404 with "message not found" and "The requested resource (Not Found) is not available."

Here is my web.xml which is located at /WebContent/WEB-INF/web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>TestREST2</display-name>
<welcome-file-list>
    <welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
  <description>JAX-RS Tools Generated - Do not modify</description>
  <servlet-name>JAX-RS Servlet</servlet-name>
  <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
      <param-name>com.sun.jersey.config.property.packages</param-name>
      <param-value>TestREST</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>  
  </servlet>
    <servlet-mapping>
      <servlet-name>JAX-RS Servlet</servlet-name>
      <url-pattern>/jaxrs/*</url-pattern>
    </servlet-mapping>
</web-app>

Here is my Java class:

package TestREST;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

// Plain old Java Object it does not extend as class or implements 
// an interface

// The class registers its methods for the HTTP GET request using the @GET annotation. 
// Using the @Produces annotation, it defines that it can deliver several MIME types,
// text, XML and HTML. 

// The browser requests per default the HTML MIME type.

//Sets the path to base URL + /hello
@Path("/hello")
public class Hello {

  // This method is called if TEXT_PLAIN is request
  @GET
  @Produces(MediaType.TEXT_PLAIN)
  public String sayPlainTextHello() {
    return "Hello Jersey";
  }

  // This method is called if XML is request
  @GET
  @Produces(MediaType.TEXT_XML)
  public String sayXMLHello() {
    return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
  }

  // This method is called if HTML is request
  @GET
  @Produces(MediaType.TEXT_HTML)
  public String sayHtmlHello() {
    return "<html> " + "<title>" + "Hello Jersey" + "</title>"
        + "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
  }   
}

I also have a JAX-RS User Library configured and referenced that includes all the JAX-RS jars.

Thoughts on what would cause the web service to not be found?

Upvotes: 27

Views: 48834

Answers (5)

Michal Gajdos
Michal Gajdos

Reputation: 10379

Jersey 2.0 does not recognize init-param with name com.sun.jersey.config.property.packages (web.xml). Try to change it to jersey.config.server.provider.packages as described in ServerProperties.PROVIDER_PACKAGES.

UPDATE (2020): try this link for current apidocs ServerProperties.PROVIDER_PACKAGES:

Upvotes: 28

Sourav Purakayastha
Sourav Purakayastha

Reputation: 775

Recently I found myself stuck in this problem. I have got it resolved by following these two points as the solution:

  1. By making the src/main/java as the source directory, and keeping the Project Structure as shown below:

enter image description here

  1. Changing com.sun.jersey.config.property.packages to jersey.config.server.provider.packages in the web.xml

Upvotes: 0

spt025
spt025

Reputation: 2304

I would like to add one answer in this post.I was struggling with same problem for two days and couldn't find the solution. I tried all the possible solutions provided here but later on I realized that server was giving error of

 org.glassfish.jersey.servlet.ServletContainer ClassNotFoundException

This link answers gives the solution if somebody is stuck like me.. org.glassfish.jersey.servlet.ServletContainer ClassNotFoundException

Actually first answer given in this post suggest the solution which is for jersey 2.x bundle and if you are using jersey 1.x then it will keep on giving error.

Kindly refer to link given in answer for further reference

Upvotes: 3

Arvind Choudhary
Arvind Choudhary

Reputation: 1

Simply by modifying the configuration of Apache Tomcat v7.0 while creating Dynamic Web Project, to include REST, I solved my problem. It is not enabled by default.

Upvotes: 0

Suren Konathala
Suren Konathala

Reputation: 3597

Thanks a lot.. i've been fighting for it as well.

This combination worked for me: Tomcat 7.0.55 Eclipse Luna Java 1.6 Jersey 1.7

web.xml:

<servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
      <param-name>jersey.config.server.provider.packages</param-name>
      <param-value>com.trgr.cobalt.cmdb.jersey.resource;com.trgr.cobalt.cmdb.jersey.beans;com.trgr.cobalt.cmdb.elasticity</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup> 
  </servlet>
  <servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/rest/*</url-pattern>
  </servlet-mapping>

Upvotes: 6

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