CODEWITHSUNDEEP
phpjavascriptjquery
mughees ilyas
mughees ilyas

Reputation: 526

jquery loop not working with php data

well i am trying to assign values to my array in jquery its not working properly if i do it without for loop like i did for 0th element its working fine but if i put it in loop it goes undefined

var array1=<?php echo json_encode($array2)?>;
var array2=<?php echo json_encode($array1)?>;
var chartData = [
    {
    student:  array1[0] ,
    marks: array2[0]
        }
];
var x=<?php echo json_encode($tquiz) ?>;
for (var i=1;i <= x ;i++ )
{
    chartData[i]=[
                    {
                     student :array1[i],                        
                     marks:array2[i]
                    }
                 ]    
}

Upvotes: 3

Views: 107

Answers (2)

Maxim Zhukov
Maxim Zhukov

Reputation: 10140

for (var i=1;i <= x ;i++ )
{
    chartData[i]=[
                {student :array1[i],

                marks:array2[i]
              }
             ]

}

change to

for (var i=1;i <= x ;i++ )
{
    chartData.push({student :array1[i], marks:array2[i]});
}

By the way, i could refactor your finally code like this:

var array1=<?php echo json_encode($array2)?>;
var array2=<?php echo json_encode($array1)?>;
var x=<?php echo json_encode($tquiz) ?>;

var chartData = [];
for (var i=0;i <= x ;i++ ) {
    chartData.push({student :array1[i], marks:array2[i]});
}

Upvotes: 1

Code Lღver
Code Lღver

Reputation: 15603

Use the foreach loop instead of for loop and here is problem in your for loop also:

It should be:

for (var i=1;i <= x.length ;i++ )

I recommend to you to use the foreach loop:

$.each( x, function( key, value ) {

Upvotes: 0

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