Reputation: 3
Hi I'm trying to use the name of the executable and an usage string, I'm using argv[0]
for such purpose but instead of the name of the executable itself it gives me the complete path to it.
Is there any way to get only the executable name?
Upvotes: 0
Views: 1173
Reputation: 637
You could use getprogname()
if the name of the program is set by your OS.
Upvotes: 0
Reputation: 2666
If it's available on your platform, there's a function char *basename(char *path)
. See basename documentation.
Upvotes: 1
Reputation: 17797
As far as I know, (on linux, at least) you just have to extract the executable name from the char* yourself.
The easiest way to do that is to use basename(argv[0])
, which you can get by including "libgen.h".
Upvotes: 4
Reputation: 76531
Just search for the last /.
const char *exename = strrchr(argv[0], '/');
if (exename)
// skip past the last /
++exename;
else
exename = argv[0];
Upvotes: 5
Reputation: 54605
Just use the last part of the path-string. Some combination of a call to strrchr
(get last path delimiter) and e.g. strcpy
or similar to copy out the part from last path delimiter to end
Upvotes: 0
Reputation: 28425
Use GetModuleFileName http://msdn.microsoft.com/en-us/library/ms683197%28VS.85%29.aspx with the handle argument = 0
Upvotes: 0