CODEWITHSUNDEEP
pythonstringdictionarygrouping
Shengen
Shengen

Reputation: 73

how to group new dictionaries by using common strings from my dictionary

Refer to my previous question: How to extract the common words before particular symbol and find particular word

mydict = {"g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt" : 0,
          "g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt" : 1,
          "g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt" : 2,
          "g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt" : 3,
          "g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt" : 4,
          "g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt" : 5,
          "h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt" : 6,
          "g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt" : 7,
          "h18_84pp_3A_MVP2_GoodiesT1-HKJ-DFG-CMVP2_Y1000-FIX.txt" : 8,
          "h18_84pp_3A_MVP3_GoodiesT1-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 9,
          "p18_84pp_2B_MVP1_GoodiesT2-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 10}

and I already got my OutputNameDict,

OutputNameDict = {'h18_84pp_3A_MVP_FIX': 1, 'p18_84pp_2B_MVP_FIX': 2, 'g18_84pp_2A_MVP_MIX': 0}

Now what I want to do is to group three new dictionaries by using my common strings CaseNameString(refer to previous question) and values from OutputNameDict.

The idea result will like:

Group1. mydict0 using value 0 in OutputNameDict and string g18_84pp_2A_MVP_GoodiesT0 inCaseNameString.

mydict0 = {"g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt" : 0,               
           "g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt" : 1,
           "g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt" : 2,
           "g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt" : 3,
           "g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt" : 4,
           "g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt" : 5,
           "g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt" : 6}

Group2. mydict1 using value 1 in OutputNameDict and string h18_84pp_3A_MVP_GoodiesT1 inCaseNameString. 

mydict1 ={"h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt" : 0,
          "h18_84pp_3A_MVP2_GoodiesT1-HKJ-DFG-CMVP2_Y1000-FIX.txt" : 1,
          "h18_84pp_3A_MVP3_GoodiesT1-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 2}

Group3. mydict2 using value 2 in OutputNameDict and string p18_84pp_2B_MVP_GoodiesT2 inCaseNameString. 

mydict2 ={"p18_84pp_2B_MVP1_GoodiesT2-HKJ-DFG-CMVP3_Y1000-FIX.txt" : 0}

Any suggestion? Is there any function to call?

Upvotes: 0

Views: 100

Answers (1)

mtadd
mtadd

Reputation: 2555

I'd change your OutputNameDict keys to be regular expression patterns, as follows:

OutputNameDict = {'h18_84pp_3A_MVP.*FIX': 1, 'p18_84pp_2B_MVP.*FIX': 2, 'g18_84pp_2A_MVP.*MIX': 0}

Then, using the re regular expression module, use that to match against the keys in mydict, and place the dictionary element into the appropriate key in output_dicts dictionary, as follows

import collections
import re
output_dicts = collections.defaultdict(dict)

for k, v in mydict.iteritems():
    for pattern, suffix in OutputNameDict.iteritems():
        if re.match(pattern,k):
            output_dicts['mydict' + str(suffix)][k] = v
            break
    else:
        output_dicts['not matched'][k] = v

This results in the output_dicts dictionary populated as follows

for k, v in output_dicts.iteritems():
    print k
    print v
    print

Which outputs

mydict1
{'h18_84pp_3A_MVP2_GoodiesT1-HKJ-DFG-CMVP2_Y1000-FIX.txt': 8, 
 'h18_84pp_3A_MVP3_GoodiesT1-HKJ-DFG-CMVP3_Y1000-FIX.txt': 9, 
 'h18_84pp_3A_MVP1_GoodiesT1-HKJ-DFG-CMVP1_Y1000-FIX.txt': 6}

mydict0
{'g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt': 0,
 'g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt': 1, 
 'g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt': 3, 
 'g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt': 4, 
 'g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt': 2, 
 'g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt': 5, 
 'g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt': 7}

mydict2
{'p18_84pp_2B_MVP1_GoodiesT2-HKJ-DFG-CMVP3_Y1000-FIX.txt': 10}

Upvotes: 1

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