CODEWITHSUNDEEP
phpisset
Pranav Raj S
Pranav Raj S

Reputation: 86

isset($_POST['submit']) not working

if condition is not working here. i've gone through the earlier solutions but i didn't find a right solution . i couldn't understand the reason . please help me out

<?php
require'core.inc.php';
require'connect.inc.php';
include 'header.php';

if(isset($_POST['submit'])) {
    $query="INSERT INTO college (CollegeName) VALUES ('".$_POST['college']."')";
    $result=mysql_query($query) or die(mysql_error());
    header('Location:index.php');
}
?>

<form action="insert.php" method="POST">
    <input type="text" name="college">
    <input type="submit" value="submit" value="Submit">
</form>

 <?php include'footer.php';?>

Upvotes: 0

Views: 8984

Answers (2)

Joe Ng&#39;ethe
Joe Ng&#39;ethe

Reputation: 870

Also, this method is not the best practice for it doesn't work on Internet Explorer. At the time of writing these i had tried it on IE 8. I find most programmers using this method for one reason or another. My two coin cents would be to check if a POST method has been requested. Please see how you could approach it below.

if($_SERVER['REQUEST_METHOD'] == 'POST'){ //if a request has been made, do something. Example post or email your data }

Upvotes: 2

Yogesh Suthar
Yogesh Suthar

Reputation: 30488

You have two value here in <input>, 1 at least should be name. Also there is no <button>, so remove the Submit</button>.

 <input type="submit" value="submit" value="Submit">Submit</button>
                      ^^^^^          ^^^^^          ^^^^^^^^^^^^^^^

should be

<input type="submit" name="submit" value="Submit"/>

Upvotes: 11

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