CODEWITHSUNDEEP
bashglob
Steve Weston
Steve Weston

Reputation: 19677

Pattern matching within a string

I am writing a bash script that contained a command similar to:

echo Configure with --with-foo=\"/tmp/foo-*\"

I wanted this command to produce output such as:

Configure with --with-foo="/tmp/foo-1.3.2"

but the pattern wasn't expanded because it was embedded within a string. I got it to work by using command substitution:

echo Configure with --with-foo=\"$(echo /tmp/foo-*)\"

I think this is the standard /bin/sh solution, but does bash support a solution that doesn't require forking a sub-shell, in the same way that $((6 * 7)) can be used in place of $(expr 6 \* 7)? Also, is there a way to restrict the result to a single match?

Upvotes: 1

Views: 189

Answers (2)

Birei
Birei

Reputation: 36282

As alternative, use a for loop and break after first iteration:

shopt -s nullglob
for f in /tmp/foo-*; do 
    echo "Configure with --with-foo=\"$f\""
    break
done

Upvotes: 1

glenn jackman
glenn jackman

Reputation: 247210

To check how many files your pattern expands into, store the expansion into an array before using it

shopt -s nullglob
foo=(/tmp/foo-*)
if   (( ${#foo[@]} == 0 )); then echo "no foo files"
elif (( ${#foo[@]}  > 1 )); then echo "too many foo files"
else do something with "${foo[0]}"
fi

Upvotes: 1

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