Reputation: 1007
I have a line of code that is:
if not hasattr(class.a, u'c'):
return
How do I mock out class so that class.a.c returns False for hasattr?
If I do this:
>>> from mock import MagicMock
>>> mock_class = MagicMock(spec=[u'a'])
>>> hasattr(mock_class, u'a')
True
>>> hasattr(mock_class, u'b')
False
>>> hasattr(mock_class.a, u'c')
True
Although I dont spec class.a.c, its being mocked!!!
Upvotes: 17
Views: 7408
Reputation: 887
You can delete the attribute, which will cause hasattr
to return False
.
From the Documentation:
>>> mock = MagicMock()
>>> hasattr(mock, 'm')
True
>>> del mock.m
>>> hasattr(mock, 'm')
False
>>> del mock.f
>>> mock.f
Traceback (most recent call last):
...
AttributeError: f
For your specific example, since mock_class.a
is another Mock, you can do del mock_class.a.c
.
Upvotes: 7
Reputation: 1076
Actually mock_class.a
will create another MagicMock, which don't have a spec. The only way I can think of is to assign the attribute a
of the mock_class
with another MagicMock with spec, like this:
mock_class = MagicMock(spec=[u'a'])
mock_class.a = MagicMock(spec=[u'a'])
hasattr(mock_class.a, u'c') # returns False
Also if you have some real objects you want to mock, there is a possibility to do some recursive autospecing.
Upvotes: 11