CODEWITHSUNDEEP
phpmysqlarrays
Mariangela Vidotto
Mariangela Vidotto

Reputation: 89

Message array to string conversion

That might be a fool question, but I need to know how to solve this: Notice: Array to string conversion in C:\xampp\htdocs\search_view.php on line 248 Why am I getting this message, what can I do to solve it?

echo'<div id="thumb"> 

'.$ids = array();
$ids[] = $results['idGames'];  
for ($i = 0; $i < count($ids); $i++) {

$id = $ids[$i];




$v  = $results['total_votes'];
$tv = $results['total_value'];
if ($v)
    $rat = $tv / $v;
else
    $rat = 0;



$j  = $ids[$i];
$id = $ids[$i];
echo '<div class="topcontentstar">

    <div id="' . $id . '" class="">';
for ($k = 1; $k < 6; $k++) {
 if ($rat + 1 > $k)
    $class = "" . $k . "  ratings_stars_index ratings_vote";
    else
    $class = "" . $k . " ratings_stars_index ratings_blank";
     echo '<div class="' . $class . '"></div>';
}
echo ' 
</div>
    </div></div>;

Upvotes: 2

Views: 6230

Answers (4)

user1646111
user1646111

Reputation:

Because in this part of code you tried to convert an array to string via concatenation

echo'<div id="thumb"> 
(line 248) '.$ids = array();

Separate them: $ids = array()

echo'<div id="thumb"> 
(line 248) ';
$ids = array();

Upvotes: 3

Amal Murali
Amal Murali

Reputation: 76636

You're doing this:

echo'<div id="thumb"> 
(line 248) '.$ids = array();

Basically, you can't concatenate array with a string and that's why the error appears.

To fix the error, you can separate the array declaration into a separate line:

echo'<div id="thumb">';
$ids = array();

Hope this helps!

Upvotes: 1

Ben Harris
Ben Harris

Reputation: 1793

As a side note, I can see a problem in your last few lines:

echo ' 
</div>
    </div></div>;

Should be:

echo '</div></div></div>';

Upvotes: -1

Hidde
Hidde

Reputation: 11951

echo'<div id="thumb"> 


(line 248) '.$ids = array();

You are concatenating a string and an array, just as the errors says. You are echoing the string, and appending the array $ids to that. Because assigning a value gets a higher precedence than concatenating things, $ids is already an array.

Upvotes: 2

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