Reputation: 708
I'm trying to crate a chain provider for login form in my Symfony2 application (version 2.3) - this is my security Yaml:
jms_security_extra:
secure_all_services: false
expressions: true
security:
encoders:
Symfony\Component\Security\Core\User\User: plaintext
FOS\UserBundle\Model\UserInterface: sha512
role_hierarchy:
ROLE_ADMIN: ROLE_USER
ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]
providers:
chain_provider:
chain:
providers: [in_memory, fos_userbundle]
fos_userbundle:
id: fos_user.user_provider.username
in_memory:
memory:
users:
admin: { password: god, roles: [ 'ROLE_ADMIN' ] }
firewalls:
main:
pattern: ^/
form_login:
provider: chain_provider
csrf_provider: form.csrf_provider
logout: true
anonymous: true
security: true
access_control:
- { path: ^/login$, role: IS_AUTHENTICATED_ANONYMOUSLY }
#- { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY, requires_channel: https }
- { path: ^/register, role: IS_AUTHENTICATED_ANONYMOUSLY }
- { path: ^/resetting, role: IS_AUTHENTICATED_ANONYMOUSLY }
- { path: ^/admin/, role: ROLE_ADMIN }
- { path: ^/group/, role: ROLE_ADMIN }
As you can see, I'm using FOSUserBundle (great stuff btw).
The problem is that after I login with in_memory admin user, I can't get to the /profile/ URL. I'm getting this error msg:
AccessDeniedHttpException: This user does not have access to this section
I found a cause to this - the problem is in FOS\UserBundle\Controller\ProfileController class:
public function showAction()
{
$user = $this->container->get('security.context')->getToken()->getUser();
if (!is_object($user) || !$user instanceof UserInterface) {
throw new AccessDeniedException('This user does not have access to this section.');
}
return $this->container->get('templating')->renderResponse('FOSUserBundle:Profile:show.html.'.$this->container->getParameter('fos_user.template.engine'), array('user' => $user));
}
The Controller is checking if $user object is an instance of UserInterface, which is not, because it is instance of Symfony\Component\Security\Core\User\User (plaintext encoder class).
I tried to change encoder configuration to this:
security:
encoders:
Symfony\Component\Security\Core\User\UserInterface: plaintext
But it didn't work. I found that the User class is hardcoded in numerous places with the Symfony engine.
So my question is: how to change that behaviour from security yaml? Am I missing something?
Upvotes: 2
Views: 4432
Reputation: 12033
Sorry, but you cant see the profile of memory user's. Profile is made only for FOS users. Thats why it must implement FOS\UserBundle\Model\UserInterface
.
Upvotes: 0
Reputation: 52493
instanceof is smart enough to know that a class that implements an interface is an instance of the interface
Symfony\Component\Security\Core\User\UserInterface implements AdvancedUserInterface which implements UserInterface.
Your problem is not the typeof
check in FOS\UserBundle\Controller\ProfileController
but a wrong firewall configuration or the in-memory user not receiving it's roles correctly!
Upvotes: 3