CODEWITHSUNDEEP
phpfilevariables
Alessandro
Alessandro

Reputation: 519

PHP - write variable output to file

I'd like to write the content of the variable $rows into the file out.txt.

The variable $rows is placed within a while loop and can be constituted by several different rows retrieved from a database.

Unfortunately, the following code just writes one single line (the last one precisely) of the expected output.

$myFile = "/var/www/test/out.txt";
$fh = fopen($myFile, 'w') or die("can't open file");
$content = $rows['text'];
fwrite($fh, $content);
fclose($fh);

Here is the PHP code (which is working) that allows me to see the contents of the $rows variable in the browser.

<?
if(isset($_POST['type'], $_POST['topic'], $_POST['tense'], $_POST['polarity']))
{
     $tipo = $_POST['type'];
     $argomento = $_POST['topic'];
     $tempo = $_POST['tense'];
     $segno = $_POST['polarity'];
   foreach ($tipo as $key_tipo => $value_tipo)
   {
         foreach ($argomento as $key_argomento => $value_argomento)
         {
                 foreach ($tempo as $key_tempo => $value_tempo)
                 {
                         foreach ($segno as $key_segno => $value_segno)
                         {
       $q_tip_arg_tem_seg = "SELECT * FROM entries WHERE type = '".$value_tipo."' AND topic = '".$value_argomento."' AND tense = '".$value_tempo."' AND polarity = '".$value_segno."'";  
       $qu_tip_arg_tem_seg = mysql_query($q_tip_arg_tem_seg);
       while ($rows = mysql_fetch_array($qu_tip_arg_tem_seg))
        {
            echo $rows['type']."<br />";
        }
   }
   }
   }
   }
}
else
{
   echo "You forgot to check something."."<br>"."Please select at least one type, topic, tense and polarity value."."<br>";
}
?>

Can you help me out? Thanks.

Upvotes: 0

Views: 4517

Answers (3)

Bart Friederichs
Bart Friederichs

Reputation: 33521

You only write out one line to the file. You probably want something like this:

$myFile = "/var/www/test/out.txt";
$fh = fopen($myFile, 'w') or die("can't open file");
if ($fh) {
    while ($row = getrow()) {
        $content = $rows['text'];
        fwrite($fh, $content); // perhaps add a newline?
    }
    fclose($fh);
}

So, open the file, write all your stuff in it, then close it.

Upvotes: 2

RiggsFolly
RiggsFolly

Reputation: 94662

If you just want to see what the array looks like, try just using print_r() it prints an array in a nice to read format.

If you want a more structured layout this will probably not be enough.

$myFile = "/var/www/test/out.txt";

$fh = fopen($myFile, 'w') or die("can't open file");

fwrite($fh, print_r($rows,TRUE) );

fclose($fh);

Upvotes: 0

sudhakar
sudhakar

Reputation: 572

you can do it in two ways

1.get the details from out.txt file first and then concat it with your $row .now you have the content already present in out.txt and also $row text.finaly write the file with content.

2.collect all rows in a single variable by concating it into a varialble.and do the file write operation.

Upvotes: 0

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