CODEWITHSUNDEEP
c#wpfvisual-studio-2012
Philip Crumpton
Philip Crumpton

Reputation: 127

C# WPF Application Open Regular Windows Form First

I have a WPF application and want to launch a regular Windows Form first by default. It will be an options panel, basically.

edit: for clarification, I'd like the Windows Form to be the only form that opens automatically. I'll then show the WPF form later.

I tried modifying App.xaml:

<Application x:Class="The_Name_Of_My.App"
         xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
         xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
         StartupUri="Form1.cs">
<Application.Resources>

I get an error: "Cannot locate resource 'form1.cs'." Am I just spinning my wheels here and trying to do something stupid when I should be making the options panel in WPF?

Upvotes: 2

Views: 4360

Answers (2)

SIAMAK RAJABI
SIAMAK RAJABI

Reputation: 1

I have same problem for loading Windows_Form_Application as default. But the answer is below... just add a Windows_Form in your project and replace below code to MainWindow.xaml.cs 

    public MainWindow()
    {
        InitializeComponent();

        //Make WPF form unvisible
        this.AllowsTransparency = true;
        this.Background = null;
        this.WindowStyle = WindowStyle.None;

        //Run windows from
        Form1 u = new Form1();
        u.Show();
        //Set close handle to form
        u.FormClosing += new System.Windows.Forms.FormClosingEventHandler(this.Form1_FormClosing);
    }

    private void Form1_FormClosing(object sender, EventArgs e)
    {
        //close WPF form if windows form being close
        this.Close();
    }

that's it...

Upvotes: 0

JMK
JMK

Reputation: 28059

Just instantiate the Windows form in your WPF Form's/Viewmodels constructor and call ShowDialog:

namespace WpfApplication11
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

            var form1 = new Form1();
            form1.ShowDialog();

            Close();
        }
    }
}

Upvotes: 3

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