CODEWITHSUNDEEP
pythonlong-integerpython-2.xstring-conversion
Shrikanth Kalluraya
Shrikanth Kalluraya

Reputation: 1119

Avoid L suffix for Long in python

I have a dictionary which may have long values for some key. I want to convert this dictionary to string and send it to a server. But when I am converting it to a string using str(dict) function for the values which have a long value is suffixed with 'L'. This when I am sending it to a server the value it is generating a problem. So can anyone suggest me a easier way of what I can do to avoid the 'L' suffix

Upvotes: 3

Views: 3506

Answers (3)

Ulrich Eckhardt
Ulrich Eckhardt

Reputation: 17415

Unrolling gnibbler's code is close to this:

# put all key-value-pairs into a list, formatted as strings
tmp1 = []
for i in D.items()
    tmp2 = "{}: {}".format(*i)
    tmp1.append(tmp2)

# create a single string by joining the elements with a comma
tmp3 = ", ".join(tmp1)

# add curly braces
tmp4 = "{{{}}}".format(tmp3)

# output result
print tmp4

The inner part of his construction is called a generator expression. They are a bit more efficient, because they don't require the temporary list (or tuple) "tmp1" and allow very terse syntax. Further, they can make code almost unreadable for people not familiar with the construct, if you have that problem try reading it from the inside out. ;^)

Upvotes: 0

Phil Cooper
Phil Cooper

Reputation: 5877

I'm not sure what your use case is but to solve this problem and quite possibly the next problem you'll have I'd suggest using json.

import json
a = {'a': 10, 'b': 1234567812345678L}
print json.dumps(a)

# output:
{"a": 10, "b": 1234567812345678}

Upvotes: 3

John La Rooy
John La Rooy

Reputation: 304137

This is because calling str on the dict will still call repr to get the representation of it's contents.

You should just write your own function to iterate over the dict

>>> D = {10000000000000000+n:n for n in range(10)}
>>> print D
{10000000000000000L: 0, 10000000000000001L: 1, 10000000000000002L: 2, 10000000000000003L: 3, 10000000000000004L: 4, 10000000000000005L: 5, 10000000000000006L: 6, 10000000000000007L: 7, 10000000000000008L: 8, 10000000000000009L: 9}
>>> print "{{{}}}".format(', '.join("{}: {}".format(*i) for i in D.items()))
{10000000000000000: 0, 10000000000000001: 1, 10000000000000002: 2, 10000000000000003: 3, 10000000000000004: 4, 10000000000000005: 5, 10000000000000006: 6, 10000000000000007: 7, 10000000000000008: 8, 10000000000000009: 9}

Upvotes: 1

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