CODEWITHSUNDEEP
androidinteger
A.J
A.J

Reputation: 333

Check entered value is number or not

I've tried this snippet, but it doesn't work

try 
    {
    Integer.parseInt(enteredID.getText().toString());
    Log.i("enteredID value", "enterdID is numeric!!!!!!!!!!!^^^");
    flag=1;
} catch (NumberFormatException e) {
    flag=-1;
    Log.i("enteredID value", "enterdID isn't numeric!!!!!!!!!!!^^^");
}

take care that it can accept either username or id to check the value, I don't want it to accept only numbers!!

Upvotes: 17

Views: 39087

Answers (13)

user10263947
user10263947

Reputation: 

/**
 * If @param digit is null or not any of the numbers - @return false.
 */
static boolean isNumber(String digit) {
    try {
        Double.parseDouble(digit);
    } catch (NullPointerException | NumberFormatException ignored) {
        return false;
    }
    return true;
}

Upvotes: 0

Daniel Luna Vazquez
Daniel Luna Vazquez

Reputation: 1

on the activity simply add inside the android:inputType="number"

Upvotes: 0

Vishudh Sasidharan
Vishudh Sasidharan

Reputation: 383

I use this function for checking three digit Integer and Float values with two positions after decimal point. If you don't want to limit number of digits, remove the {x,x} from the regular expression. 

private boolean isNumeric(String string) {
     if(Pattern.matches("\\d{1,3}((\\.\\d{1,2})?)", string))
          return true;
     else
          return false;
}

Upvotes: 0

Maysam R
Maysam R

Reputation: 969

use this method

 boolean isNumber(String string) {
    try {
      int amount = Integer.parseInt(string);
      return true;
    } catch (Exception e) {
      return false;
    }
  }

like this :

if (isNumber(input)) {
  // string is int
}

Upvotes: 2

pm dubey
pm dubey

Reputation: 1016

String text = editText123.getText().toString();
try {
   int num = Integer.parseInt(text);
   Log.i("",num+" is a number");
} catch (NumberFormatException e) {
   Log.i("",text+" is not a number");
}

Upvotes: 0

Ramesh Kumar
Ramesh Kumar

Reputation: 1249

If boolean value is true then it is number otherwise string value

boolean digitsOnly = TextUtils.isDigitsOnly(editText.getText());

or for Example

String text = edt_email.getText().toString();
            boolean digitsOnly = TextUtils.isDigitsOnly(text);
            if (digitsOnly) {
                 if (text.length() == 0) {
                    Toast.makeText(getApplicationContext(), "field can't be empty.", Toast.LENGTH_LONG).show();
                 } else {
                   Toast.makeText(getApplicationContext(), "field is int value", Toast.LENGTH_LONG).show();
                 }
            }else {
                    Toast.makeText(getApplicationContext(), "Field is string value", Toast.LENGTH_LONG).show();
                }
            }

Upvotes: 23

Aditi
Aditi

Reputation: 455

Use TextUtils class function for that

TextUtils.isDigitsOnly("gifg");

it will return true if only digits are there and false if any character exists inside string

Upvotes: 5

rikin patoliya
rikin patoliya

Reputation: 1

Pattern ptrn = Pattern.compile(regexStr);

if (!ptrn.matcher(et_number.getText().toString().trim()).matches()) {

    //write code here for success

}else{

    //write code here for success

}

Upvotes: 0

David N
David N

Reputation: 519

Try with this regular expression :

String regex = "-?\\d+(\\.\\d+)?";

if (enteredID.getText().toString().matches(regex))  {
     Log.i("enteredID value", "enterdID is numeric!!!!!!!!!!!^^^");
     flag=1;
 } else {
     flag=-1;
     Log.i("enteredID value", "enterdID isn't numeric!!!!!!!!!!!^^^");
 }

Upvotes: 5

Dhaval Patel
Dhaval Patel

Reputation: 694

Use this expression for validate number only

String regexStr = "^[0-9]*$";

if(et_number.getText().toString().trim().matches(regexStr))
{
    //write code here for success
}
else{
    // write code for failure
}

Upvotes: 21

s.d
s.d

Reputation: 29436

Perhaps something like this:

    String text = enteredID.getText().toString();

    if(text.matches("\\w+")){
      //--words--
    }else if (text.matches("\\d+")){
      //--numeric--
    }else {
      //-- something else --
    }

You can change the regex to match complex formats.

Upvotes: 0

Scott Helme
Scott Helme

Reputation: 4799

You should never use an exception in this way really. When you expect an exception to be thrown like this you should find an alternative way of handling it.

Try using: http://developer.android.com/reference/android/widget/TextView.html#setRawInputType%28int%29

Something like this should do it:

editText.setInputType(InputType.TYPE_CLASS_NUMBER | InputType.TYPE_NUMBER_FLAG_DECIMAL | InputType.TYPE_NUMBER_FLAG_SIGNED);

Upvotes: 0

Muhammad Aamir Ali
Muhammad Aamir Ali

Reputation: 21117

set EditText proprerty inputType = number it will always take numbers as input

android:inputType="number"

Upvotes: 7

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