CODEWITHSUNDEEP
javascriptjquery
user2137186
user2137186

Reputation: 837

Comparing two arrays in jquery

Using this code...

var a = ['volvo','random data'];
var b = ['random data'];
var unique = $.grep(a, function(element) {
    return $.inArray(element, b) == -1;
});

var result = unique ;

alert(result);

...I am able to find which element of Array "a" is not in Array "b".

Now I need to find:

For example "Random data" is in both arrays, so I need to return its position in Array b which is zero index.

Upvotes: 3

Views: 42155

Answers (5)

Prince Prasad
Prince Prasad

Reputation: 1678

Convert both array to string and compare

if (JSON.stringify(a) == JSON.stringify(b))
{
    // your code here
}

Upvotes: 6

Matthias Holdorf
Matthias Holdorf

Reputation: 1050

Regarding your comment, here is a solution:

with jQuery:

$.each( a, function( key, value ) {
    var index = $.inArray( value, b );
    if( index != -1 ) {
        console.log( index );
    }
});

without jQuery:

a.forEach( function( value ) {
    if( b.indexOf( value ) != -1 ) {
       console.log( b.indexOf( value ) );
    }
});

Upvotes: 6

L10
L10

Reputation: 389

You can try this:

var a = ['volvo','random data'];
var b = ['random data'];
$.each(a,function(i,val){
var result=$.inArray(val,b);
if(result!=-1)
alert(result); 
})

Upvotes: 1

Vivek Pradhan
Vivek Pradhan

Reputation: 4847

This should probably work:

  var positions = [];
  for(var i=0;i<a.length;i++){
  var result = [];
       for(var j=0;j<b.length;j++){
          if(a[i] == b[j])
            result.push(i); 
  /*result array will have all the positions where a[i] is
    found in array b */
       }
  positions.push(result);
 /*For every i I update the required array into the final positions
   as I need this check for every element */ 
 }

So your final array would be something like:

  var positions = [[0,2],[1],[3]...] 
  //implies a[0] == b[0],b[2], a[1] == b[1] and so on.

Hope it helps

Upvotes: 1

user1983983
user1983983

Reputation: 4841

You could just iterate over a and use Array.prototype.indexOf to get the index of the element in b, if indexOf returns -1 b does not contain the element of a.

var a = [...], b = [...]
a.forEach(function(el) {
    if(b.indexOf(el) > 0) console.log(b.indexOf(el));
    else console.log("b does not contain " + el);
});

Upvotes: 1

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