CODEWITHSUNDEEP
c++arraysstring
user2604063
user2604063

Reputation: 1

How to split a full=number into two groups according to their position(even or odd)

I need to split a txt file into 2 arrays The txt file contains full number.Can I do it without string? For example,for input

4(how many line)
2 1
3 7
8 0
3 7

I want array 1 contains (firt number in a line)

{2 
3 
8 
3}

array 2 contains (second number in a line)

{1 
 7
 0 
 7}

How can I do that?Just curious...Here is a code which does not work..

ifstream ifs("sth.txt");
int g;
ifs>>g;
int girl[g];
int boy[g];
for(int i=0;i<2*g,i++;){
if (i%2==0)ifs>>gil[g];
if (i%2==1)ifs>>boy[g];}
cout<<boy[1];

Upvotes: 0

Views: 175

Answers (2)

Lemonade
Lemonade

Reputation: 503

ifstream ifs("sth.txt"); 
int g;
ifs>>g;
int girl[g];
int boy[g];
for(int i=0;i<g,i++;){
    ifs>>gil[i];
    ifs>>boy[i];
}
cout<<boy[0];

or

int a =0; b = 0;
for(int i=0;i<g;i++){
     if(i%2) ifs>>boy[b++];
     else ifs>>girl[a++];
}

or 

for(int i=1;i<=g;i+=2){
    ifs>>boy[(i-1)/2];
    if(i+1<=g)
        ifs>>girl[(i-1)/2];
}

or

std::string str((std::istreambuf_iterator<char>(ifs)), std::istreambuf_iterator<char>());
for(int i=0;i<g;i++){
  fscanf(str,"%d %d",boy[i],girl[i]);
}

Upvotes: -1

Ari
Ari

Reputation: 3127

ifstream ifs("sth.txt");
int g;
ifs>>g;
int girl[g];
int boy[g];
for(int i=0;i<g,i++;){
    ifs>>girl[i];
    ifs>>boy[i];
}
cout<<boy[0];

You were reading to girl[g] and boy[g] instead of 0..(g-1).

I also changed reading: two ints insted of 1 in one iteration of the loop.

At the end I changed counting first (index 0) instead of second element of boy.

Upvotes: 2

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