CODEWITHSUNDEEP
c#linq
scarpacci
scarpacci

Reputation: 9194

LINQ Get Distinct values and fill LIST

I am trying to figure out if I can use LINQ to provide me with the distinct values of some data I have in a DataTable (FirstName, LastName, QTY). I can get the distinct values and fill my List, but I have to run two different LINQ queries to get it....I am sure there is a better way to do it :)

Any suggestions would be greatly appreciated (very new to LINQ)

Code: 

public static List<StudentData> LinqDistinct(DataTable dt)
{
      DataTable linqTable = dt;

       //get the distinct values
        var query =
            (from names in dt.AsEnumerable()
             select new {
                 FirstName = names.Field<string>("FirstName"),
                 LastName = names.Field<string>("LastName")
             }).Distinct();


        //fill my list with the distinct values
        List<StudentData> sList = (from sa in query.AsEnumerable()
                                   select new StudentData
                                              {
                                                  FirstName = sa.FirstName,
                                                  LastName = sa.LastName
                                                  //Qty = names.Field<int>("Qty")

                                                 }).ToList();                                               



        return sList;}

Upvotes: 21

Views: 81878

Answers (4)

ShuggyCoUk
ShuggyCoUk

Reputation: 36438

Any reason not to simply do the projection after the distinct, you might need an AsEnumerable() after the Distinct but that's not a big deal.

public static List<StudentData> LinqDistinct(DataTable dt)
{
    DataTable linqTable = dt;
    return
        (from names in dt.AsEnumerable()
         select new {
             FirstName = names.Field<string>("FirstName"),
             LastName = names.Field<string>("LastName")
         }).Distinct().Select(x =>
             new StudentData() { FirstName=x.FirstName, LastName=x.LastName})
             .ToList();
}

Upvotes: 25

Joel Mueller
Joel Mueller

Reputation: 28765

It's not clear from your question whether the quantity is a value in your DataTable, or a count of the number of duplicates for a given item, as in Ecyrb's answer. However, if your StudentData class implements IEquatable<StudentData> or overrides the Equals method, this should work:

public static List<StudentData> LinqDistinct(DataTable dt)
{
    return dt.AsEnumerable()
             .Select(row => new StudentData
                            {
                                FirstName = row.Field<string>("FirstName"),
                                LastName = row.Field<string>("LastName"),
                                Qty = row.Field<int>("Qty")
                            })
             .Distinct()
             .ToList();
}

If StudentData doesn't support value comparison, and you can't add that support to the class, you may have to create an implementation of IEqualityComparer<StudentData> and pass that into the Distinct method.

Upvotes: 5

Ecyrb
Ecyrb

Reputation: 2080

You could use GroupBy:

public static List<StudentData> LinqDistinct(DataTable dt)
{
    List<StudentData> results = dt.AsEnumerable()
        .GroupBy(row => 
        {
            FirstName = row.Field<string>("FirstName"),
            LastName = row.Field<string>("LastName")
        })
        .Select(group => new StudentData
        {
            FirstName = group.Key.FirstName,
            LastName = group.Key.LastName,
            Qty = group.Count()
        })
        .ToList();

    return results;
}

class StudentData
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public int Qty { get; set; }
}

Upvotes: 1

bytebender
bytebender

Reputation: 7491

Pretty sure you could just do this...

List<StudentData> sList = (from names in dt.AsEnumerable().Distinct() // I am not sure if you even have to call AsEnumerable()
                 select new StudentData() {
                     FirstName = names.Field<string>("FirstName"),
                     LastName = names.Field<string>("LastName")
                 }).ToList();

Upvotes: 1

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