CODEWITHSUNDEEP
phparrays
EJK
EJK

Reputation: 326

str_replace in array, and append text at the end

So I'm kind of stuck on this - I'm looking to replace text in an array (easily done via str_replace), but I would also like to append text onto the end of that specific array. For example, my original array is:

Array (

[1] => DTSTART;VALUE=DATE:20130712
[2] => DTEND;VALUE=DATE:20130713
[3] => SUMMARY:Vern
[4] => UID:1fb5aa60-ff89-429e-80fd-ad157dc777b8
[5] => LAST-MODIFIED:20130711T010042Z
[6] => SEQUENCE:1374767972

)

I would like to search that array for ";VALUE=DATE" and replace it with nothing (""), but would also like to insert a text string 7 characters after each replace ("T000000"). So my resulting array would be:

Array (

[1] => DTSTART:20130712T000000
[2] => DTEND:20130713T000000
[3] => SUMMARY:Vern
[4] => UID:1fb5aa60-ff89-429e-80fd-ad157dc777b8
[5] => LAST-MODIFIED:20130711T010042Z
[6] => SEQUENCE:1374767972

)

Is something like this possible using combinations of str_replace, substr_replace, etc? I'm fairly new to PHP and would love if someone could point me in the right direction! Thanks much

Upvotes: 1

Views: 1533

Answers (4)

Leonardo Sapuy
Leonardo Sapuy

Reputation: 2740

for($i=0;$i<count($array);$i++){
   if(strpos($array[$i], ";VALUE=DATE")){//look for the text into the string
      //Text found, let's replace and append
      $array[$i]=str_replace(";VALUE=DATE","",$array[$i]);
      $array[$i].="T000000";
   }
   else{
      //text not found in that position, will not replace
      //Do something
   }
}

If you want just to replace, just do it

$array=str_replace($array,";VALUE=DATE","");

And will replace all the text in all the array's positions...

Upvotes: 0

Jon
Jon

Reputation: 437376

You can use preg_replace as an one-stop shop for this type of manipulation:

$array = preg_replace('/(.*);VALUE=DATE(.*)/', '$1$2T000000', $array);

The regular expression matches any string that contains ;VALUE=DATE and captures whatever precedes and follows it into capturing groups (referred to as $1 and $2 in the replacement pattern). It then replaces that string with $1 concatenated to $2 (effectively removing the search target) and appends "T000000" to the result.

Upvotes: 4

Jason McCreary
Jason McCreary

Reputation: 72981

The naive approach would be to loop over each element and check for ;VALUE=DATE. If it exists, remove it and append T000000.

foreach ($array as $key => $value) {
  if (strpos($value, ';VALUE=DATE') !== false) {
    $array[$key] = str_replace(";VALUE=DATE", "", $value) . "T000000";
  }
}

Upvotes: 1

Bad Wolf
Bad Wolf

Reputation: 8349

You are correct str_replace() is the function that you are looking for. In addition you can use the concatenation operator . to append your string to the end of the new string. Is this what you are looking for?

$array[1] = str_replace(";VALUE=DATE", "", $array[1])."T000000";
$array[2] = str_replace(";VALUE=DATE", "", $array[2])."T000000";

Upvotes: 0

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