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Zack Peterson
Zack Peterson

Reputation: 57343

Why am I getting this Javascript runtime error?

I've got the following JavaScript on my web page...

64    var description = new Array();
65    description[0] = "..."
66    description[1] = "..."
...
78    function init() {
79        document.getElementById('somedivid').innerHTML = description[0];
80    }
81
82    window.onload = init();

In Microsoft Internet Explorer it causes the following error...

A Runtime Error has occurred.
Do you wish to debug?

Line: 81
Error: Not implemented

javascript runtime error

Line 79 executes as expected.

If line 79 is commented out, it still throws the error.

If I comment out line 82, then the function does not execute and there is no error.

Upvotes: 4

Views: 6083

Answers (5)

Tomalak
Tomalak

Reputation: 338208

Try to add an envent listener for 'load' instead, or use the declarative syntax <body onload="init()">.

EDIT: Additionally, saying window.onload = init(); sets window.onload to the result of calling init(). What you mean is window.onload = init; (a lambda expression). This is bad practice still, as it overwrites other things that might be bound to window.onload.

Upvotes: 1

edosoft
edosoft

Reputation: 17271

Try running it in FireFox with the FireBug plugin enabled. This will allow you to debug the javascript

Upvotes: 0

Jacob
Jacob

Reputation: 10692

To preserve any previously set onload functions try this

var prevload = window.onload;
window.onload = function(){
    prevload();
    init();
}

Upvotes: 2

J c
J c

Reputation: 6413

In addition to the onload fixes proposed here, also check to see if there are multiple elements with that ID, I believe IE will return a collection of all elements with that ID, in which case you would need to select the intended item out of the collection before accessing that property or ensure you are using unique IDs.

Upvotes: 0

Ateş G&#246;ral
Ateş G&#246;ral

Reputation: 140050

Shouldn't line 82 read:

window.onload = init;

When you do "init()" it's a call to a function that returns void. You end up calling that function before the page loads.

Upvotes: 13

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